| Phone | ||
|---|---|---|
| Dinner dance | 55% | 80% |
| Football game | 20% | 10% |
| Picnic | 20% | 5% |
| Pool party | 5% | 5% |
| Total | 100% | 100% |
An alumni association survey asked each high school graduate to select the one activity he or she preferred for the association’s next event. Some of the people responded by phone, and the others responded by email. The table above shows the distribution of preferred activity, in percent, for each response type used. For the survey, the number of email responses was twice the number of phone responses. If a person who preferred a picnic is selected at random, what is the probability that the person responded by email?
Correct answer: 1/3 (parsed from the explanation — this source omits an answer key for this item)
Explanation
The correct answer is . It’s given that the number of email responses is twice the number of phone responses. Therefore, if the number of phone responses is p, then the number of email responses is
. The table shows that 20% of people who responded by phone preferred a picnic. It follows that the expression
represents the number of these people. The table also shows that 5% of the people who responded by email preferred a picnic. The expression
, or
, represents the number of these people. Therefore, a total of
, or
people preferred a picnic. Thus, the probability of selecting at random a person who responded by email from the people who preferred a picnic is
, or
. Note that 1/3, .3333, and 0.333 are examples of ways to enter a correct answer.
Loading…
Searched on YouTube by topic, not by question text. Open this search on YouTube →
SAT® and PSAT/NMSQT® are trademarks registered by the College Board, which is not affiliated with, does not sponsor, and does not endorse this project.