sat-dog

182 The correct answer is . Let s represent the number of small candles the owner , can purchase, and let represent the number of large candles the owner can $4.90 purchase. It’s given that the owner pays per candle to purchase small $11.60 candles and per candle to purchase large candles. Therefore, the owner 4.90 11.60, , pays s dollars for s small candles and dollars for large candles, 4.90 +11.60, which means the owner pays a total of s dollars to purchase $2,200 candles. It’s given that the owner budgets to purchase candles. Therefore, 4.90 +11.60,#2,200 s . It’s also given that the owner must purchase a minimum 200 +,$200 4.90 +11.60,#2,200 of candles. Therefore, s . The inequalities s +,$200 and s can be combined into one compound inequality by rewriting the second inequality so that its left-hand side is equivalent to the left-hand side of , +,$200 the first inequality. Subtracting from both sides of the inequality s $200-, 4.90 yields s . Multiplying both sides of this inequality by yields 4.90 $4.90 200-, 4.90 $980-4.90, 11.60, s ^ h, or s . Adding to both sides 4.90 +11.60,$980-4.90,+11.60, of this inequality yields s , or 4.90 +11.60,$980+6.70, s . This inequality can be combined with the 4.90 +11.60,#2,200 inequality s , which yields the compound inequality 980+6.70,#4.90 +11.60,#2,200 980+6.70,#2,200 s . It follows that . 980 6.70,#1,220 Subtracting from both sides of this inequality yields . Dividing 6.70 ,#182.09 both sides of this inequality by yields approximately . Since the number of large candles the owner purchases must be a whole number, the maximum number of large candles the owner can purchase is the largest whole 182.09 182 number less than , which is .