sat-dog

= = 2-12 = The correct answer is 6. It’s given that y 4x and y x . Since y 4x, substituting 4x for y in the second equation of the given system yields 4 = 2-12 x x . Subtracting 4x from both sides of this equation yields 0= 2-4 -12 0= -6 +2 x x . This equation can be rewritten as ^x h^x h. By the zero -6=0 +2=0 product property, x or x . Adding 6 to both sides of the equation -6=0 = +2=0 x yields x 6. Subtracting 2 from both sides of the equation x =- yields x 2. Therefore, solutions to the given system of equations occur when = =- x 6 and when x 2. It’s given that a solution to the given system of equations 2 is ^x,yh, where x 0. Since 6 is greater than 0, it follows that the value of x is 6.