sat-dog

Choice D is correct. It’s given that for the linear function g, the table shows four values of x and their corresponding values of g^xh. It’s also given that the = + function can be written as g^xh mx b, where m and b are constants. The table 32 shows that when the value of x is 1, the corresponding value of g^xh is . 32 = + 32= 1 + Substituting 1 for x and for g^xh in g^xh mx b yields m^ h b, or 32= + 32- = m b. Subtracting b from both sides of this equation yields b m. The table also shows that when the value of x is 2, the corresponding value of g^xh is 28 28 = + 28= 2 + . Substituting 2 for x and for g^xh in g^xh mx b yields m^ h b, or 28=2 + 32- 28=2 32- + m b. Substituting b for m in this equation yields ^ bh b. Applying the distributive property to the right-hand side of this equation yields 28=64-2 + 28=64- 64 b b, or b. Subtracting from both sides of this equation -36=- - 36= yields b. Dividing both sides of this equation by 1 yields b. Choice A is incorrect and may result from conceptual or calculation errors. Choice B is incorrect and may result from conceptual or calculation errors. Choice C is incorrect and may result from conceptual or calculation errors.