sat-dog

64 2 3-56 3 Choice D is correct. For the expression t s t s, 4 is a common factor of 64 56 2 2 3 3 and , t is a common factor of t and t , and s is a common factor of s 4 2 and s. It follows that t s is a common factor of each term in the given 36 SAT PRACTICE TEST #11 ANSWER EXPLANATIONS SAT ANSWER EXPLANATIONS n MATH: MODULE 1 4 2 64 2 3-56 3 expression. Factoring out t s from each term in the expression t s t s 4 2 16 2-14 4 2 16 2-14 yields t s^ s th. Therefore, t s^ s th is equivalent to 64 2 3-56 3 t s t s. 64 3-56 2 2 Choice A is incorrect. This expression is equivalent to ts t s , not 64 2 3-56 3 t s t s. Choice B is incorrect. This expression is equivalent to 64 3 3-56 2 64 2 3-56 3 t s t s, not t s t s. Choice C is incorrect. This expression is 64 3 2-56 2 2 64 2 3-56 3 equivalent to t s t s , not t s t s.