sat-dog

The correct answer is $\frac{1}{4}$. It's given that line $k$ is defined by $y=\frac{1}{4}x+1$. It's also given that line $j$ is parallel to line $k$ in the xy-plane. A line in the xy-plane represented by an equation in slope-intercept form $y=mx+b$ has a slope of $m$ and a y-intercept of $\left(0,b\right)$. Therefore, the slope of line $k$ is $\frac{1}{4}$. Since parallel lines have equal slopes, the slope of line $j$ is $\frac{1}{4}$. Note that 1/4 and .25 are examples of ways to enter a correct answer.