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Choice C is correct. A system of two linear equations in two variables, $x$ and $y$, has no solution if the graphs of the lines represented by the equations in the xy-plane are distinct and parallel. The graphs of two lines in the xy-plane represented by equations in slope-intercept form, $y=mx+b$, where $m$ and $b$ are constants, are parallel if their slopes, $m$, are the same and are distinct if their y-coordinates of the y-intercepts, $b$, are different. In the equations $y=16x+3$ and $y=16x+19$, the values of $m$ are each $16$, and the values of $b$ are $3$ and $19$, respectively. Since the slopes of these lines are the same, and the y-coordinates of the y-intercepts are different, it follows that the system of linear equations in choice C has no solution. 

Choice A is incorrect. The lines represented by the equations in this system are a vertical line and a horizontal line. Therefore, this system has a solution, $\left(3,5\right)$, rather than no solution.

Choice B is incorrect. The two lines represented by these equations have different slopes and the same y-coordinate of the y-intercept. Therefore, this system has a solution, $\left(0,6\right)$, rather than no solution.

Choice D is incorrect. The two lines represented by these equations are a horizontal line and a line with a slope of $5$ that have the same y-coordinate of the y-intercept. Therefore, this system has a solution, $\left(0,5\right)$, rather than no solution.