sat-dog

Choice A is correct. It’s given that the function $F\left(x\right)=\frac{9}{5}\left(x-273.15\right)+32$ gives the temperature, in degrees Fahrenheit, that corresponds to a temperature of $x$ kelvins. A temperature that increased by $2.10$ kelvins means that the value of $x$ increased by $2.10$ kelvins. It follows that an increase in $x$ by $2.10$ increases $F\left(x\right)$ by $\frac{9}{5}\left(2.10\right)$, or $3.78$. Therefore, if a temperature increased by $2.10$ kelvins, the temperature increased by $3.78$ degrees Fahrenheit.

Choice B is incorrect and may result from conceptual or calculation errors.

Choice C is incorrect and may result from conceptual or calculation errors.

Choice D is incorrect and may result from conceptual or calculation errors.