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The correct answer is $\mathrm{2,216}$. The surface area of a prism is the sum of the areas of all its faces. A right rectangular prism consists of six rectangular faces, where opposite faces are congruent. It's given that this prism has a length of $28 \text{cm}$, a width of $15 \text{cm}$, and a height of $16 \text{cm}$. Thus, for this prism, there are two faces with area $\left(28\right)\left(15\right) {\text{cm}}^2$, two faces with area $\left(28\right)\left(16\right) {\text{cm}}^2$, and two faces with area $\left(15\right)\left(16\right) {\text{cm}}^2$. Therefore, the surface area, $\text{in} {\text{cm}}^2$, of the right rectangular prism is $2\left(28\right)\left(15\right)+2\left(28\right)\left(16\right)+2\left(15\right)\left(16\right)$, or $\mathrm{2,216}$.