sat-dog

The correct answer is $\mathrm{1,015}$. It’s given that the first moon orbits the planet every $252$ days. Therefore, it takes the first moon $252\left(29\right)$, or $\mathrm{7,308}$, days to orbit the planet $29$ times. It’s also given that the second moon orbits the planet every $287$ days. Therefore, it takes the second moon $287\left(29\right)$, or $\mathrm{8,323}$, days to orbit the planet $29$ times. Since it takes the first moon $\mathrm{7,308}$ days and the second moon $\mathrm{8,323}$ days, it takes the second moon $\mathrm{8,323}-\mathrm{7,308}$, or $\mathrm{1,015}$, more days than it takes the first moon to orbit the planet $29$ times.