A rectangular volleyball court has an area of 162 square meters. If the length of the court is twice the width, what is the width of the court, in meters?
A
9
B
18
C
27
D
54
Correct answer: A
Explanation
Choice A is correct. It’s given that the volleyball court is rectangular and has an area of 162 square meters. The formula for the area of a rectangle is , where A is the area, is the length, and w is the width of the rectangle. It’s also given that the length of the volleyball court is twice the width, thus . Substituting the given value into the formula for the area of a rectangle and using the relationship between length and width for this rectangle yields . This equation can be rewritten as . Dividing both sides of this equation by 2 yields . Taking the square root of both sides of this equation yields . Since the width of a rectangle is a positive number, the width of the volleyball court is 9 meters.
Choice B is incorrect because this is the length of the rectangle. Choice C is incorrect because this is the result of using 162 as the perimeter rather than the area. Choice D is incorrect because this is the result of calculating w in the equation instead of .
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id cb_question_bank:1f3d49aa-cfa7-4c10-a000-3b71e2f7b76b · question f89af023 · IBN 021775-DC
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