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In a set of four consecutive odd integers, where the integers are ordered from least to greatest, the first integer is represented by x. The product of 12 and the fourth odd integer is at most 26 less than the sum of the first and third odd integers. Which inequality represents this situation? 12(x+6) ≤ x+(x+4)−26
Correct answer: A (parsed from the explanation — this source omits an answer key for this item)
Explanation
Choice A is correct. It’s given that the four odd integers are consecutive, ordered from least to greatest, and that the first odd integer is represented by x. It follows + that the second odd integer is represented by x 2, the third odd integer is + + represented by x 4, and the fourth odd integer is represented by x 6. 12 Therefore, the product of and the fourth odd integer is represented by 12 +6 26 ^x h, and less than the sum of the first and third odd integers is + +4 -26 12 represented by x ^x h . Since the product of and the fourth odd 26 integer is at most less than the sum of the first and third odd integers, it 12 +6 # + +4 -26 follows that ^x h x ^x h . Choice B is incorrect and may result from conceptual or calculation errors. Choice C is incorrect and may result from conceptual or calculation errors. Choice D is incorrect and may result from conceptual or calculation errors.
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