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Choice A is correct. In each choice, the values of x are 2, 4, and 6. Substituting 24 2+8 216 the first value of x, 2, for x in the given inequality yields y ^ h , or y . = 16 Therefore, when x 2, the corresponding value of y must be greater than . Of the given choices, only choice A is a table where the value of y corresponding to = 16 x 2 is greater than . To confirm that the other values of x in this table and their corresponding values of y are also solutions to the given inequality, the values of x and y in the table can be substituted for x and y in the given 30 inequality. Substituting 4 for x and for y in the given inequality yields 3024 4+8 30224 41 ^ h , or , which is true. Substituting 6 for x and for y in the 4124 6+8 41232 given inequality yields ^ h , or , which is true. It follows that for choice A, all the values of x and their corresponding values of y are solutions to the given inequality. Choice B is incorrect. Substituting 2 for x and 8 for y in the given inequality 824 2+8 8216 yields ^ h , or , which is false. Choice C is incorrect. Substituting 2 13 1324 2+8 13216 for x and for y in the given inequality yields ^ h , or , which is 13 false. Choice D is incorrect. Substituting 2 for x and for y in the given 1324 2+8 13216 inequality yields ^ h , or , which is false. 36 SAT PRACTICE TEST #6 ANSWER EXPLANATIONS SAT ANSWER EXPLANATIONS n MATH: MODULE 1