{"id":"cb_question_bank:dc43dcbf-4d99-43e8-9baa-5075708e49e1","source_id":"cb_question_bank","source_item_id":"dc43dcbf-4d99-43e8-9baa-5075708e49e1","external_id":"eb64b8f6-731a-4137-9ed2-358ab19f106c","ibn":null,"question_id":"6f6dfe3e","program":"SAT","module":"math","domain_code":"H","domain":"Algebra","skill_code":"H.C.","skill":"Linear equations in two variables","difficulty":"M","score_band":5,"answer_type":"mcq","answer_source":"key","layout_warning":null,"form_id":null,"module_number":null,"position":null,"stem":"x y negative 6 n plus 184 negative 3 n plus 92 0 n The table shows three values of x and their corresponding values of y , where n is a constant, for the linear relationship between x and y . What is the slope of the line that represents this relationship in the xy -plane?","stimulus":"","stimulus_html":null,"stem_html":"<figure class=\"table\"><table border=\"1\">\n<tbody>\n<tr>\n<th style=\"width: 47.7651%; text-align: center;\" scope=\"col\"><math alttext=\"x\"><mi>x</mi>\n</math></th>\n<th style=\"width: 47.7651%; text-align: center;\" scope=\"col\"><math alttext=\"y\"><mi>y</mi>\n</math></th>\n</tr>\n<tr>\n<td style=\"width: 47.7651%; text-align: center;\"><math alttext=\"negative 6\"><mo>-</mo><mn>6</mn>\n</math></td>\n<td style=\"width: 47.7651%; text-align: center;\"><math alttext=\"n plus 184\"><mrow>\n\t<mi>n</mi>\n\t<mo>+</mo>\n\t<mn>184</mn>\n</mrow>\n</math></td>\n</tr>\n<tr>\n<td style=\"width: 47.7651%; text-align: center;\"><math alttext=\"negative 3\"><mo>-</mo><mn>3</mn>\n</math></td>\n<td style=\"width: 47.7651%; text-align: center;\"><math alttext=\"n plus 92\"><mrow>\n\t<mi>n</mi>\n\t<mo>+</mo>\n\t<mn>92</mn>\n</mrow>\n</math></td>\n</tr>\n<tr>\n<td style=\"width: 47.7651%; text-align: center;\"><math alttext=\"0\"><mn>0</mn>\n</math></td>\n<td style=\"width: 47.7651%; text-align: center;\"><math alttext=\"n\"><mi>n</mi>\n</math></td>\n</tr>\n</tbody>\n</table></figure>\n<p style=\"text-align: left;\">The table shows three values of <math alttext=\"x\"><mi>x</mi>\n</math> and their corresponding values of <math alttext=\"y\"><mi>y</mi>\n</math>, where <math alttext=\"n\"><mi>n</mi>\n</math> is a constant, for the linear relationship between <math alttext=\"x\"><mi>x</mi>\n</math> and <math alttext=\"y\"><mi>y</mi>\n</math>. What is the slope of the line that represents this relationship in the <em>xy</em>-plane?</p>","rationale_html":"<p>Choice A is correct. The slope, <math alttext=\"m\"><mi>m</mi>\n</math>, of a line in the <em>xy</em>-plane can be found using two points on the line, <math alttext=\"left parenthesis x 1 comma y 1 right parenthesis\"><mfenced><mrow><msub><mi>x</mi><mn>1</mn></msub><mo>,</mo><msub><mi>y</mi><mn>1</mn></msub></mrow></mfenced></math> and&nbsp;<math alttext=\"left parenthesis x 2 comma y 2 right parenthesis\"><mfenced><mrow><msub><mi>x</mi><mn>2</mn></msub><mo>,</mo><msub><mi>y</mi><mn>2</mn></msub></mrow></mfenced></math>, and the slope formula <math alttext=\"m equals StartFraction y 2 minus y 1 Over x 2 minus x 1 EndFraction\"><mi>m</mi><mo>=</mo><mfrac><mrow><msub><mi>y</mi><mn>2</mn></msub><mo>-</mo><msub><mi>y</mi><mn>1</mn></msub></mrow><mrow><msub><mi>x</mi><mn>2</mn></msub><mo>-</mo><msub><mi>x</mi><mn>1</mn></msub></mrow></mfrac></math>. Based on the given table, the line representing the relationship between <math alttext=\"x\"><mi>x</mi>\n</math> and <math alttext=\"y\"><mi>y</mi>\n</math> in the <em>xy</em>-plane passes through the points <math alttext=\"left parenthesis negative 6 comma n plus 184 right parenthesis\"><mfenced><mrow><mo>-</mo><mn>6</mn><mo>,</mo><mi>n</mi><mo>+</mo><mn>184</mn></mrow></mfenced></math>, <math alttext=\"left parenthesis negative 3 comma n plus 92 right parenthesis\"><mfenced><mrow><mo>-</mo><mn>3</mn><mo>,</mo><mi>n</mi><mo>+</mo><mn>92</mn></mrow></mfenced></math>, and <math alttext=\"left parenthesis 0 comma n right parenthesis\"><mfenced><mrow><mn>0</mn><mo>,</mo><mi>n</mi></mrow></mfenced></math>, where <math alttext=\"n\"><mi>n</mi>\n</math> is a constant. Substituting two of these points,&nbsp;<math alttext=\"left parenthesis negative 3 comma n plus 92 right parenthesis\"><mfenced><mrow><mo>-</mo><mn>3</mn><mo>,</mo><mi>n</mi><mo>+</mo><mn>92</mn></mrow></mfenced></math> and <math alttext=\"left parenthesis 0 comma n right parenthesis\"><mfenced><mrow><mn>0</mn><mo>,</mo><mi>n</mi></mrow></mfenced></math>, for&nbsp;<math alttext=\"left parenthesis x 1 comma y 1 right parenthesis\"><mfenced><mrow><msub><mi>x</mi><mn>1</mn></msub><mo>,</mo><msub><mi>y</mi><mn>1</mn></msub></mrow></mfenced></math> and <math alttext=\"left parenthesis x 2 comma y 2 right parenthesis\"><mfenced><mrow><msub><mi>x</mi><mn>2</mn></msub><mo>,</mo><msub><mi>y</mi><mn>2</mn></msub></mrow></mfenced></math>, respectively, in the slope formula yields <math alttext=\"m equals StartFraction n minus left parenthesis n plus 92 right parenthesis Over 0 minus left parenthesis negative 3 right parenthesis EndFraction\"><mi>m</mi><mo>=</mo><mfrac><mrow><mi>n</mi><mo>-</mo><mfenced><mrow><mi>n</mi><mo>+</mo><mn>92</mn></mrow></mfenced></mrow><mrow><mn>0</mn><mo>-</mo><mfenced><mrow><mo>-</mo><mn>3</mn></mrow></mfenced></mrow></mfrac></math>, which is equivalent to <math alttext=\"m equals StartFraction n minus n minus 92 Over 0 plus 3 EndFraction\"><mi>m</mi><mo>=</mo><mfrac><mrow><mi>n</mi><mo>-</mo><mi>n</mi><mo>-</mo><mn>92</mn></mrow><mrow><mn>0</mn><mo>+</mo><mn>3</mn></mrow></mfrac></math>, or <math alttext=\"m equals negative StartFraction 92 Over 3 EndFraction\"><mi>m</mi><mo>=</mo><mo>-</mo><mfrac><mn>92</mn><mn>3</mn></mfrac></math>. Therefore, the slope of the line that represents this relationship in the <em>xy</em>-plane is <math alttext=\"negative StartFraction 92 Over 3 EndFraction\"><mrow>\n\t<mo>-</mo>\n\t<mfrac>\n\t\t<mn>92</mn>\n\t\t<mn>3</mn>\n\t</mfrac>\n</mrow>\n</math>.</p>\n<p>Choice B is incorrect and may result from conceptual or calculation errors.</p>\n<p>Choice C is incorrect and may result from conceptual or calculation errors.</p>\n<p>Choice D is incorrect and may result from conceptual or calculation errors.</p>","correct_answer":["A"],"has_media":false,"has_mathml":true,"has_table":true,"source_created_at":"2023-08-02T20:25:59.815000+00:00","source_updated_at":"2023-08-02T20:25:59.815000+00:00","options":[{"label":"A","content_html":"<p><math alttext=\"negative StartFraction 92 Over 3 EndFraction\"><mrow>\n\t<mo>-</mo>\n\t<mfrac>\n\t\t<mn>92</mn>\n\t\t<mn>3</mn>\n\t</mfrac>\n</mrow>\n</math></p>","ord":0},{"label":"B","content_html":"<p><math alttext=\"negative three ninety seconds\"><mrow>\n\t<mo>-</mo>\n\t<mfrac>\n\t\t<mn>3</mn>\n\t\t<mn>92</mn>\n\t</mfrac>\n</mrow>\n</math></p>","ord":1},{"label":"C","content_html":"<p><math alttext=\"StartFraction n plus 92 Over negative 3 EndFraction\"><mfrac><mrow><mi>n</mi><mo>+</mo><mrow><mn>92</mn></mrow></mrow><mrow><mo>-</mo><mrow><mn>3</mn></mrow></mrow></mfrac></math></p>","ord":2},{"label":"D","content_html":"<p><math alttext=\"StartFraction 2 n minus 92 Over 3 EndFraction\"><mfrac><mrow><mn>2</mn><mi>n</mi><mo>-</mo><mrow><mn>92</mn></mrow></mrow><mrow><mn>3</mn></mrow></mfrac></math></p>","ord":3}],"attribution":{"source_id":"cb_question_bank","source_name":"College Board digital SAT question bank (community dump)","rights_holder":"College Board","canonical_url":"https://satsuitequestionbank.collegeboard.org/","retrieved_from":"https://raw.githubusercontent.com/mdn522/sat-question-bank/main/data/cb-digital-questions.json","attribution":"SAT practice questions © College Board, from the official SAT Suite Question Bank. Retrieved via the community dump at github.com/mdn522/sat-question-bank.","disclaimer":"SAT® and PSAT/NMSQT® are trademarks registered by the College Board, which is not affiliated with, does not sponsor, and does not endorse this project.","license":"College Board copyright; source repository carries no licence. Local use only.","redistributable":false,"item_count":2017}}