{"id":"cb_question_bank:cadae8a7-8f51-471c-bb42-032a9a5054a9","source_id":"cb_question_bank","source_item_id":"cadae8a7-8f51-471c-bb42-032a9a5054a9","external_id":null,"ibn":"09404-DC","question_id":"3e9cc0c2","program":"SAT","module":"math","domain_code":"P","domain":"Advanced Math","skill_code":"P.A.","skill":"Equivalent expressions","difficulty":"M","score_band":5,"answer_type":"mcq","answer_source":"key","layout_warning":null,"form_id":null,"module_number":null,"position":null,"stem":"Which of the following is equivalent to ?","stimulus":"","stimulus_html":null,"stem_html":"

Which of the following is equivalent to \"\" ?

\n","rationale_html":"

Choice B is correct. Multiplying (1 – p) by each term of the polynomial within the second pair of parentheses gives (1 – p)1 = 1 – p; (1 – p)p = p – p2; (1 – p)p2 = p2 – p3; (1 – p)p3 = p3 – p4; (1 – p)p4 = p4 – p5; (1 – p)p5 = p5 – p6; and (1 – p)p6 = p6 – p7. Adding these seven expressions together and combining like terms gives 1 + (p – p) + (p2 – p2) + (p3 – p3) + (p4 – p4) + (p5 – p5) + (p6 – p6) – p7, which can be simplified to 1 – p7.


\n\tChoices A, C, and D are incorrect and may result from incorrectly identifying the highest power of p in the expressions or incorrectly combining like terms.

 

\n","correct_answer":["B"],"has_media":true,"has_mathml":false,"has_table":false,"source_created_at":"2023-08-02T20:25:59.637000+00:00","source_updated_at":"2023-08-02T20:25:59.637000+00:00","options":[{"label":"A","content_html":"

\"1

\n","ord":0},{"label":"B","content_html":"

\"1

\n","ord":1},{"label":"C","content_html":"

\"1

\n","ord":2},{"label":"D","content_html":"

\"1

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