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style=\"text-align: left;\">The correct answer is&nbsp;<math alttext=\"24.5\"><mn>24.5</mn></math>. It's given that a triangle is formed by connecting the three points shown, which are&nbsp;<math alttext=\"left parenthesis negative 3 comma 4 right parenthesis\"><mfenced><mrow><mo>-</mo><mn>3</mn><mo>,</mo><mn>4</mn></mrow></mfenced></math>,&nbsp;<math alttext=\"left parenthesis 5 comma 3 right parenthesis\"><mfenced><mrow><mn>5</mn><mo>,</mo><mn>3</mn></mrow></mfenced></math>, and&nbsp;<math alttext=\"left parenthesis 4 comma negative 3 right parenthesis\"><mfenced><mrow><mn>4</mn><mo>,</mo><mo>-</mo><mn>3</mn></mrow></mfenced></math>. Let this triangle be triangle A. The area of triangle A can be found by calculating the area of the rectangle that circumscribes it and subtracting the areas of the three triangles that are inside the rectangle but outside triangle A. The rectangle formed by the points <math alttext=\"left parenthesis negative 3 comma 4 right parenthesis\"><mfenced><mrow><mo>-</mo><mn>3</mn><mo>,</mo><mn>4</mn></mrow></mfenced></math>,&nbsp;<math alttext=\"left parenthesis 5 comma 4 right parenthesis\"><mfenced><mrow><mn>5</mn><mo>,</mo><mn>4</mn></mrow></mfenced></math>,&nbsp;<math alttext=\"left parenthesis 5 comma negative 3 right parenthesis\"><mfenced><mrow><mn>5</mn><mo>,</mo><mo>-</mo><mn>3</mn></mrow></mfenced></math>, and&nbsp;<math alttext=\"left parenthesis negative 3 comma negative 3 right parenthesis\"><mfenced><mrow><mo>-</mo><mn>3</mn><mo>,</mo><mo>-</mo><mn>3</mn></mrow></mfenced></math> circumscribes triangle A. The width, in units, of this rectangle can be found by calculating the distance between the points <math alttext=\"left parenthesis 5 comma 4 right parenthesis\"><mfenced><mrow><mn>5</mn><mo>,</mo><mn>4</mn></mrow></mfenced></math> and <math alttext=\"left parenthesis 5 comma negative 3 right parenthesis\"><mfenced><mrow><mn>5</mn><mo>,</mo><mo>-</mo><mn>3</mn></mrow></mfenced></math>. This distance is <math alttext=\"4 minus left parenthesis negative 3 right parenthesis\"><mn>4</mn><mo>-</mo><mfenced><mrow><mo>-</mo><mn>3</mn></mrow></mfenced></math>, or <math alttext=\"7\"><mn>7</mn>\n</math>. The length, in units, of this rectangle can be found by calculating the distance between the points&nbsp;<math alttext=\"left parenthesis 5 comma 4 right parenthesis\"><mfenced><mrow><mn>5</mn><mo>,</mo><mn>4</mn></mrow></mfenced></math>&nbsp;and&nbsp;<math alttext=\"left parenthesis negative 3 comma 4 right parenthesis\"><mfenced><mrow><mo>-</mo><mn>3</mn><mo>,</mo><mn>4</mn></mrow></mfenced></math>. This distance is <math alttext=\"5 minus left parenthesis negative 3 right parenthesis\"><mn>5</mn><mo>-</mo><mfenced><mrow><mo>-</mo><mn>3</mn></mrow></mfenced></math>, or <math alttext=\"8\"><mn>8</mn>\n</math>. It follows that the area, in square units, of the rectangle is <math alttext=\"left parenthesis 7 right parenthesis left parenthesis 8 right parenthesis\"><mfenced><mn>7</mn></mfenced><mfenced><mn>8</mn></mfenced></math>, or <math alttext=\"56\"><mn>56</mn>\n</math>. One of the triangles that lies inside the rectangle but outside triangle A is formed by the points&nbsp;<math alttext=\"left parenthesis negative 3 comma 4 right parenthesis\"><mfenced><mrow><mo>-</mo><mn>3</mn><mo>,</mo><mn>4</mn></mrow></mfenced></math>,&nbsp;<math alttext=\"left parenthesis 5 comma 4 right parenthesis\"><mfenced><mrow><mn>5</mn><mo>,</mo><mn>4</mn></mrow></mfenced></math>, and&nbsp;<math alttext=\"left parenthesis 5 comma 3 right parenthesis\"><mfenced><mrow><mn>5</mn><mo>,</mo><mn>3</mn></mrow></mfenced></math>. The length, in units, of a base of this triangle can be found by calculating the distance between the points <math alttext=\"left parenthesis 5 comma 4 right parenthesis\"><mfenced><mrow><mn>5</mn><mo>,</mo><mn>4</mn></mrow></mfenced></math> and <math alttext=\"left parenthesis 5 comma 3 right parenthesis\"><mfenced><mrow><mn>5</mn><mo>,</mo><mn>3</mn></mrow></mfenced></math>. This distance is <math alttext=\"4 minus 3\"><mn>4</mn><mo>-</mo><mn>3</mn></math>, or <math alttext=\"1\"><mn>1</mn>\n</math>. The corresponding height, in units, of this triangle can be found by calculating the distance between the points <math alttext=\"left parenthesis 5 comma 4 right parenthesis\"><mfenced><mrow><mn>5</mn><mo>,</mo><mn>4</mn></mrow></mfenced></math> and <math alttext=\"left parenthesis negative 3 comma 4 right parenthesis\"><mfenced><mrow><mo>-</mo><mn>3</mn><mo>,</mo><mn>4</mn></mrow></mfenced></math>. This distance is <math alttext=\"5 minus left parenthesis negative 3 right parenthesis\"><mn>5</mn><mo>-</mo><mfenced><mrow><mo>-</mo><mn>3</mn></mrow></mfenced></math>, or <math alttext=\"8\"><mn>8</mn>\n</math>. It follows that the area, in square units, of this triangle is <math alttext=\"one half left parenthesis 8 right parenthesis left parenthesis 1 right parenthesis\"><mfrac><mn>1</mn><mn>2</mn></mfrac><mfenced><mn>8</mn></mfenced><mfenced><mn>1</mn></mfenced></math>, or <math alttext=\"4\"><mn>4</mn>\n</math>. A second triangle that lies inside the rectangle but outside triangle A is formed by the points <math alttext=\"left parenthesis 4 comma negative 3 right parenthesis\"><mfenced><mrow><mn>4</mn><mo>,</mo><mo>-</mo><mn>3</mn></mrow></mfenced></math>, <math alttext=\"left parenthesis 5 comma 3 right parenthesis\"><mfenced><mrow><mn>5</mn><mo>,</mo><mn>3</mn></mrow></mfenced></math>, and <math alttext=\"left parenthesis 5 comma negative 3 right parenthesis\"><mfenced><mrow><mn>5</mn><mo>,</mo><mo>-</mo><mn>3</mn></mrow></mfenced></math>. The length, in units, of a base of this triangle can be found by calculating the distance between the points <math alttext=\"left parenthesis 5 comma 3 right parenthesis\"><mfenced><mrow><mn>5</mn><mo>,</mo><mn>3</mn></mrow></mfenced></math> and <math alttext=\"left parenthesis 5 comma negative 3 right parenthesis\"><mfenced><mrow><mn>5</mn><mo>,</mo><mo>-</mo><mn>3</mn></mrow></mfenced></math>. This distance is <math alttext=\"3 minus left parenthesis negative 3 right parenthesis\"><mn>3</mn><mo>-</mo><mfenced><mrow><mo>-</mo><mn>3</mn></mrow></mfenced></math> , or <math alttext=\"6\"><mn>6</mn>\n</math>. The corresponding height, in units, of this triangle can be found by calculating the distance between the points <math alttext=\"left parenthesis 5 comma negative 3 right parenthesis\"><mfenced><mrow><mn>5</mn><mo>,</mo><mo>-</mo><mn>3</mn></mrow></mfenced></math> and <math alttext=\"left parenthesis 4 comma negative 3 right parenthesis\"><mfenced><mrow><mn>4</mn><mo>,</mo><mo>-</mo><mn>3</mn></mrow></mfenced></math>. This distance is <math alttext=\"5 minus 4\"><mn>5</mn><mo>-</mo><mn>4</mn></math>, or <math alttext=\"1\"><mn>1</mn>\n</math>. It follows that the area, in square units, of this triangle is <math alttext=\"one half left parenthesis 1 right parenthesis left parenthesis 6 right parenthesis\"><mfrac><mn>1</mn><mn>2</mn></mfrac><mfenced><mn>1</mn></mfenced><mfenced><mn>6</mn></mfenced></math>, or <math alttext=\"3\"><mn>3</mn>\n</math>. The third triangle that lies inside the rectangle but outside triangle A is formed by the points <math alttext=\"left parenthesis negative 3 comma 4 right parenthesis\"><mfenced><mrow><mo>-</mo><mn>3</mn><mo>,</mo><mn>4</mn></mrow></mfenced></math>, <math alttext=\"left parenthesis negative 3 comma negative 3 right parenthesis\"><mfenced><mrow><mo>-</mo><mn>3</mn><mo>,</mo><mo>-</mo><mn>3</mn></mrow></mfenced></math>, and <math alttext=\"left parenthesis 4 comma negative 3 right parenthesis\"><mfenced><mrow><mn>4</mn><mo>,</mo><mo>-</mo><mn>3</mn></mrow></mfenced></math>. The length, in units, of a base of this triangle can be found by calculating the distance between the points <math alttext=\"left parenthesis 4 comma negative 3 right parenthesis\"><mfenced><mrow><mn>4</mn><mo>,</mo><mo>-</mo><mn>3</mn></mrow></mfenced></math> and <math alttext=\"left parenthesis negative 3 comma negative 3 right parenthesis\"><mfenced><mrow><mo>-</mo><mn>3</mn><mo>,</mo><mo>-</mo><mn>3</mn></mrow></mfenced></math>. This distance is <math alttext=\"4 minus left parenthesis negative 3 right parenthesis\"><mn>4</mn><mo>-</mo><mfenced><mrow><mo>-</mo><mn>3</mn></mrow></mfenced></math>, or <math alttext=\"7\"><mn>7</mn>\n</math>. The corresponding height, in units, of this triangle can be found by calculating the distance between the points <math alttext=\"left parenthesis negative 3 comma 4 right parenthesis\"><mfenced><mrow><mo>-</mo><mn>3</mn><mo>,</mo><mn>4</mn></mrow></mfenced></math> and <math alttext=\"left parenthesis negative 3 comma negative 3 right parenthesis\"><mfenced><mrow><mo>-</mo><mn>3</mn><mo>,</mo><mo>-</mo><mn>3</mn></mrow></mfenced></math>. This distance is <math alttext=\"4 minus left parenthesis negative 3 right parenthesis\"><mn>4</mn><mo>-</mo><mfenced><mrow><mo>-</mo><mn>3</mn></mrow></mfenced></math>, or <math alttext=\"7\"><mn>7</mn>\n</math>. It follows that the area, in square units, of this triangle is <math alttext=\"one half left parenthesis 7 right parenthesis left parenthesis 7 right parenthesis\"><mfrac><mn>1</mn><mn>2</mn></mfrac><mfenced><mn>7</mn></mfenced><mfenced><mn>7</mn></mfenced></math>, or <math alttext=\"24.5\"><mn>24.5</mn></math>. Thus, the area, in square units, of the triangle formed by connecting the three points shown is <math alttext=\"56 minus 4 minus 3 minus 24.5\"><mn>56</mn><mo>-</mo><mn>4</mn><mo>-</mo><mn>3</mn><mo>-</mo><mn>24.5</mn></math>, or&nbsp;<math alttext=\"24.5\"><mn>24.5</mn></math>. Note that 24.5 and 49/2 are examples of ways to enter a correct answer.</p>","correct_answer":["24.5","49/2"],"has_media":true,"has_mathml":true,"has_table":false,"source_created_at":"2023-08-02T20:25:59.836000+00:00","source_updated_at":"2023-08-02T20:25:59.836000+00:00","options":[],"attribution":{"source_id":"cb_question_bank","source_name":"College Board digital SAT question bank (community dump)","rights_holder":"College Board","canonical_url":"https://satsuitequestionbank.collegeboard.org/","retrieved_from":"https://raw.githubusercontent.com/mdn522/sat-question-bank/main/data/cb-digital-questions.json","attribution":"SAT practice questions © College Board, from the official SAT Suite Question Bank. Retrieved via the community dump at github.com/mdn522/sat-question-bank.","disclaimer":"SAT® and PSAT/NMSQT® are trademarks registered by the College Board, which is not affiliated with, does not sponsor, and does not endorse this project.","license":"College Board copyright; source repository carries no licence. Local use only.","redistributable":false,"item_count":2017}}