{"id":"cb_question_bank:c0b242dc-df3d-402c-ae93-5e9d71da54fe","source_id":"cb_question_bank","source_item_id":"c0b242dc-df3d-402c-ae93-5e9d71da54fe","external_id":"e7cb9147-ae39-47e9-a4cb-da0cfbf0b250","ibn":null,"question_id":"b74f2feb","program":"SAT","module":"math","domain_code":"P","domain":"Advanced Math","skill_code":"P.A.","skill":"Equivalent expressions","difficulty":"H","score_band":7,"answer_type":"spr","answer_source":"key","layout_warning":null,"form_id":null,"module_number":null,"position":null,"stem":"The expression 6 RootIndex 5 StartRoot 3 Superscript 5 Baseline x Superscript 45 Baseline EndRoot dot RootIndex 8 StartRoot 2 Superscript 8 Baseline x EndRoot is equivalent to a x Superscript b , where a and b are positive constants and x greater than 1 . What is the value of a plus b ?","stimulus":"","stimulus_html":null,"stem_html":"<p style=\"text-align: left;\">The expression <math alttext=\"6 RootIndex 5 StartRoot 3 Superscript 5 Baseline x Superscript 45 Baseline EndRoot dot RootIndex 8 StartRoot 2 Superscript 8 Baseline x EndRoot\"><mrow><mn>6</mn></mrow><mroot><mrow><msup><mrow><mn>3</mn></mrow><mrow><mn>5</mn></mrow></msup><msup><mi>x</mi><mrow><mn>45</mn></mrow></msup></mrow><mrow><mn>5</mn></mrow></mroot><mo>·</mo><mroot><mrow><msup><mn>2</mn><mrow><mn>8</mn></mrow></msup><mi>x</mi></mrow><mrow><mn>8</mn></mrow></mroot></math> is equivalent to <math alttext=\"a x Superscript b\"><mrow>\n\t<mi>a</mi>\n\t<msup>\n\t\t<mi>x</mi>\n\t\t<mi>b</mi>\n\t</msup>\n</mrow>\n</math>, where <math alttext=\"a\"><mi>a</mi>\n</math> and <math alttext=\"b\"><mi>b</mi>\n</math> are positive constants and <math alttext=\"x greater than 1\"><mi>x</mi><mo>&gt;</mo><mn>1</mn></math>. What is the value of <math alttext=\"a plus b\"><mrow>\n\t<mi>a</mi>\n\t<mo>+</mo>\n\t<mi>b</mi>\n</mrow>\n</math>?</p>","rationale_html":"<p style=\"text-align: left;\">The correct answer is <math alttext=\"StartFraction 361 Over 8 EndFraction\"><mfrac><mn>361</mn><mn>8</mn></mfrac></math>. The rational exponent property is <math alttext=\"RootIndex n StartRoot y Superscript m Baseline EndRoot equals y Superscript StartFraction m Over n EndFraction\"><mroot><msup><mi>y</mi><mi>m</mi></msup><mi>n</mi></mroot><mo>=</mo><msup><mi>y</mi><mfrac><mi>m</mi><mi>n</mi></mfrac></msup></math>, where <math alttext=\"y greater than 0\"><mi>y</mi><mo>&gt;</mo><mn>0</mn></math>, <math alttext=\"m\"><mi>m</mi>\n</math> and <math alttext=\"n\"><mi>n</mi>\n</math> are integers, and <math alttext=\"n greater than 0\"><mi>n</mi><mo>&gt;</mo><mn>0</mn></math>. This property can be applied to rewrite the given expression <math alttext=\"6 RootIndex 5 StartRoot 3 Superscript 5 Baseline x Superscript 45 Baseline EndRoot dot RootIndex 8 StartRoot 2 Superscript 8 Baseline x EndRoot\"><mn>6</mn><mroot><mrow><msup><mn>3</mn><mn>5</mn></msup><msup><mi>x</mi><mn>45</mn></msup></mrow><mn>5</mn></mroot><mo>·</mo><mroot><mrow><msup><mn>2</mn><mn>8</mn></msup><mi>x</mi></mrow><mn>8</mn></mroot></math> as&nbsp;<math alttext=\"6 left parenthesis 3 Superscript five fifths Baseline right parenthesis left parenthesis x Superscript StartFraction 45 Over 5 EndFraction Baseline right parenthesis left parenthesis 2 Superscript eight eighths Baseline right parenthesis left parenthesis x Superscript one eighth Baseline right parenthesis\"><mn>6</mn><mfenced><msup><mn>3</mn><mfrac><mn>5</mn><mn>5</mn></mfrac></msup></mfenced><mfenced><msup><mi>x</mi><mfrac><mn>45</mn><mn>5</mn></mfrac></msup></mfenced><mfenced><msup><mn>2</mn><mfrac><mn>8</mn><mn>8</mn></mfrac></msup></mfenced><mfenced><msup><mi>x</mi><mfrac><mn>1</mn><mn>8</mn></mfrac></msup></mfenced></math>, or <math alttext=\"6 left parenthesis 3 right parenthesis left parenthesis x Superscript 9 Baseline right parenthesis left parenthesis 2 right parenthesis left parenthesis x Superscript one eighth Baseline right parenthesis\"><mn>6</mn><mfenced><mn>3</mn></mfenced><mfenced><msup><mi>x</mi><mn>9</mn></msup></mfenced><mfenced><mn>2</mn></mfenced><mfenced><msup><mi>x</mi><mfrac><mn>1</mn><mn>8</mn></mfrac></msup></mfenced></math>. This expression can be rewritten by multiplying the constants, which gives <math alttext=\"36 left parenthesis x Superscript 9 Baseline right parenthesis left parenthesis x Superscript one eighth Baseline right parenthesis\"><mn>36</mn><mfenced><msup><mi>x</mi><mn>9</mn></msup></mfenced><mfenced><msup><mi>x</mi><mfrac><mn>1</mn><mn>8</mn></mfrac></msup></mfenced></math>. The multiplication exponent property is <math alttext=\"y Superscript n Baseline dot y Superscript m Baseline equals y Superscript n plus m\"><msup><mi>y</mi><mi>n</mi></msup><mo>·</mo><msup><mi>y</mi><mi>m</mi></msup><mo>=</mo><msup><mi>y</mi><mrow><mi>n</mi><mo>+</mo><mi>m</mi></mrow></msup></math>, where <math alttext=\"y greater than 0\"><mi>y</mi><mo>&gt;</mo><mn>0</mn></math>. This property can be applied to rewrite the expression <math alttext=\"36 left parenthesis x Superscript 9 Baseline right parenthesis left parenthesis x Superscript one eighth Baseline right parenthesis\"><mn>36</mn><mfenced><msup><mi>x</mi><mn>9</mn></msup></mfenced><mfenced><msup><mi>x</mi><mfrac><mn>1</mn><mn>8</mn></mfrac></msup></mfenced></math> as <math alttext=\"36 x Superscript 9 plus one eighth\"><mn>36</mn><msup><mi>x</mi><mrow><mn>9</mn><mo>+</mo><mfrac><mn>1</mn><mn>8</mn></mfrac></mrow></msup></math>, or&nbsp;<math alttext=\"36 x Superscript StartFraction 73 Over 8 EndFraction\"><mn>36</mn><msup><mi>x</mi><mfrac><mn>73</mn><mn>8</mn></mfrac></msup></math>. Therefore, <math alttext=\"6 RootIndex 5 StartRoot 3 Superscript 5 Baseline x Superscript 45 Baseline EndRoot dot RootIndex 8 StartRoot 2 Superscript 8 Baseline x EndRoot equals 36 x Superscript StartFraction 73 Over 8 EndFraction\"><mn>6</mn><mroot><mrow><msup><mn>3</mn><mn>5</mn></msup><msup><mi>x</mi><mn>45</mn></msup></mrow><mn>5</mn></mroot><mo>·</mo><mroot><mrow><msup><mn>2</mn><mn>8</mn></msup><mi>x</mi></mrow><mn>8</mn></mroot><mo>=</mo><mn>36</mn><msup><mi>x</mi><mfrac><mn>73</mn><mn>8</mn></mfrac></msup></math>. It's given that <math alttext=\"6 RootIndex 5 StartRoot 3 Superscript 5 Baseline x Superscript 45 Baseline EndRoot dot RootIndex 8 StartRoot 2 Superscript 8 Baseline x EndRoot\"><mn>6</mn><mroot><mrow><msup><mn>3</mn><mn>5</mn></msup><msup><mi>x</mi><mn>45</mn></msup></mrow><mn>5</mn></mroot><mo>·</mo><mroot><mrow><msup><mn>2</mn><mn>8</mn></msup><mi>x</mi></mrow><mn>8</mn></mroot></math> is equivalent to&nbsp;<math alttext=\"a x Superscript b\"><mi>a</mi><msup><mi>x</mi><mi>b</mi></msup></math>; therefore, <math alttext=\"a equals 36\"><mi>a</mi><mo>=</mo><mn>36</mn></math>&nbsp;and <math alttext=\"b equals StartFraction 73 Over 8 EndFraction\"><mi>b</mi><mo>=</mo><mfrac><mn>73</mn><mn>8</mn></mfrac></math>. It follows that&nbsp;<math alttext=\"a plus b equals 36 plus StartFraction 73 Over 8 EndFraction\"><mi>a</mi><mo>+</mo><mi>b</mi><mo>=</mo><mn>36</mn><mo>+</mo><mfrac><mn>73</mn><mn>8</mn></mfrac></math>. Finding a common denominator on the right-hand side of this equation gives <math alttext=\"a plus b equals StartFraction 288 Over 8 EndFraction plus StartFraction 73 Over 8 EndFraction\"><mi>a</mi><mo>+</mo><mi>b</mi><mo>=</mo><mfrac><mn>288</mn><mn>8</mn></mfrac><mo>+</mo><mfrac><mn>73</mn><mn>8</mn></mfrac></math>, or <math alttext=\"a plus b equals StartFraction 361 Over 8 EndFraction\"><mi>a</mi><mo>+</mo><mi>b</mi><mo>=</mo><mfrac><mn>361</mn><mn>8</mn></mfrac></math>. Note that 361/8, 45.12, and 45.13 are examples of ways to enter a correct answer.</p>","correct_answer":["361/8","45.12","45.13"],"has_media":false,"has_mathml":true,"has_table":false,"source_created_at":"2023-08-02T20:25:59.821000+00:00","source_updated_at":"2023-08-02T20:25:59.821000+00:00","options":[],"attribution":{"source_id":"cb_question_bank","source_name":"College Board digital SAT question bank (community dump)","rights_holder":"College Board","canonical_url":"https://satsuitequestionbank.collegeboard.org/","retrieved_from":"https://raw.githubusercontent.com/mdn522/sat-question-bank/main/data/cb-digital-questions.json","attribution":"SAT practice questions © College Board, from the official SAT Suite Question Bank. Retrieved via the community dump at github.com/mdn522/sat-question-bank.","disclaimer":"SAT® and PSAT/NMSQT® are trademarks registered by the College Board, which is not affiliated with, does not sponsor, and does not endorse this project.","license":"College Board copyright; source repository carries no licence. Local use only.","redistributable":false,"item_count":2017}}