{"id":"cb_question_bank:a5e69f0d-e3fd-4307-8261-7f31b6f986ed","source_id":"cb_question_bank","source_item_id":"a5e69f0d-e3fd-4307-8261-7f31b6f986ed","external_id":"91e78971-fbd4-44f8-ad04-97fb96cf9931","ibn":null,"question_id":"77c0cced","program":"SAT","module":"math","domain_code":"P","domain":"Advanced Math","skill_code":"P.B.","skill":"Nonlinear equations in one variable and systems of equations in two variables","difficulty":"H","score_band":7,"answer_type":"mcq","answer_source":"key","layout_warning":null,"form_id":null,"module_number":null,"position":null,"stem":"y equals 2 x squared minus 21 x plus 64 y equals 3 x plus a In the given system of equations, a is a constant. The graphs of the equations in the given system intersect at exactly one point, left parenthesis x comma y right parenthesis , in the xy -plane. What is the value of x ?","stimulus":"","stimulus_html":null,"stem_html":"<p style=\"text-align: center;\"><math alttext=\"y equals 2 x squared minus 21 x plus 64\"><mrow>\n\t<mi>y</mi>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mrow>\n\t\t\t<mn>2</mn>\n\t\t\t<msup>\n\t\t\t\t<mi>x</mi>\n\t\t\t\t<mn>2</mn>\n\t\t\t</msup>\n\t\t</mrow>\n\t\t<mo>-</mo>\n\t\t<mrow>\n\t\t\t<mn>21</mn>\n\t\t\t<mi>x</mi>\n\t\t</mrow>\n\t\t<mo>+</mo>\n\t\t<mn>64</mn>\n\t</mrow>\n</mrow>\n</math></p>\n<p style=\"text-align: center;\"><math alttext=\"y equals 3 x plus a\"><mrow>\n\t<mi>y</mi>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mrow>\n\t\t\t<mn>3</mn>\n\t\t\t<mi>x</mi>\n\t\t</mrow>\n\t\t<mo>+</mo>\n\t\t<mi>a</mi>\n\t</mrow>\n</mrow>\n</math></p>\n<p style=\"text-align: left;\">In the given system of equations, <math alttext=\"a\"><mi>a</mi>\n</math> is a constant. The graphs of the equations in the given system intersect at exactly one point, <math alttext=\"left parenthesis x comma y right parenthesis\"><mo>(</mo><mi>x</mi><mo>,</mo><mi>y</mi><mo>)</mo></math>, in the <em>xy</em>-plane. What is the value of <math alttext=\"x\"><mi>x</mi>\n</math>?</p>","rationale_html":"<p>Choice C is correct. It's given that the graphs of the equations in the given system intersect at exactly one point, <math alttext=\"left parenthesis x comma y right parenthesis\"><mfenced><mrow><mi>x</mi><mo>,</mo><mi>y</mi></mrow></mfenced></math>, in the <em>xy</em>-plane.&nbsp;Therefore, <math alttext=\"left parenthesis x comma y right parenthesis\"><mfenced><mrow><mi>x</mi><mo>,</mo><mi>y</mi></mrow></mfenced></math> is the only solution to the given system of equations. The given system of equations can be solved by subtracting the second equation, <math alttext=\"y equals 3 x plus a\"><mi>y</mi><mo>=</mo><mn>3</mn><mi>x</mi><mo>+</mo><mi>a</mi></math>, from the first equation, <math alttext=\"y equals 2 x squared minus 21 x plus 64\"><mi>y</mi><mo>=</mo><mn>2</mn><msup><mi>x</mi><mn>2</mn></msup><mo>-</mo><mn>21</mn><mi>x</mi><mo>+</mo><mn>64</mn></math>. This yields <math alttext=\"y minus y equals left parenthesis 2 x squared minus 21 x plus 64 right parenthesis minus left parenthesis 3 x plus a right parenthesis\"><mi>y</mi><mo>-</mo><mi>y</mi><mo>=</mo><mfenced><mrow><mn>2</mn><msup><mi>x</mi><mn>2</mn></msup><mo>-</mo><mn>21</mn><mi>x</mi><mo>+</mo><mn>64</mn></mrow></mfenced><mo>-</mo><mfenced><mrow><mn>3</mn><mi>x</mi><mo>+</mo><mi>a</mi></mrow></mfenced></math>, or <math alttext=\"0 equals 2 x squared minus 24 x plus 64 minus a\"><mn>0</mn><mo>=</mo><mn>2</mn><msup><mi>x</mi><mn>2</mn></msup><mo>-</mo><mn>24</mn><mi>x</mi><mo>+</mo><mn>64</mn><mo>-</mo><mi>a</mi></math>. Since the given system has only one solution, this equation has only one solution. A quadratic equation in the form <math alttext=\"r x squared plus s x plus t equals 0\"><mi>r</mi><msup><mi>x</mi><mn>2</mn></msup><mo>+</mo><mi>s</mi><mi>x</mi><mo>+</mo><mi>t</mi><mo>=</mo><mn>0</mn></math>, where <math alttext=\"r\"><mi>r</mi>\n</math>, <math alttext=\"s\"><mi>s</mi>\n</math>, and <math alttext=\"t\"><mi>t</mi>\n</math> are constants, has one solution if and only if the discriminant, <math alttext=\"s squared minus 4 r t\"><msup><mi>s</mi><mn>2</mn></msup><mo>-</mo><mn>4</mn><mi>r</mi><mi>t</mi></math>, is equal to zero. Substituting <math alttext=\"2\"><mn>2</mn>\n</math> for <math alttext=\"r\"><mi>r</mi>\n</math>, <math alttext=\"negative 24\"><mo>-</mo><mn>24</mn></math> for <math alttext=\"s\"><mi>s</mi>\n</math>, and <math alttext=\"negative a plus 64\"><mrow>\n\t<mrow>\n\t\t<mo>-</mo>\n\t\t<mi>a</mi>\n\t</mrow>\n\t<mo>+</mo>\n\t<mn>64</mn>\n</mrow>\n</math> for <math alttext=\"t\"><mi>t</mi>\n</math> in the expression <math alttext=\"s squared minus 4 r t\"><msup><mi>s</mi><mn>2</mn></msup><mo>-</mo><mn>4</mn><mi>r</mi><mi>t</mi></math> yields <math alttext=\"left parenthesis negative 24 right parenthesis squared minus left parenthesis 4 right parenthesis left parenthesis 2 right parenthesis left parenthesis 64 minus a right parenthesis\"><msup><mfenced><mrow><mo>-</mo><mn>24</mn></mrow></mfenced><mn>2</mn></msup><mo>-</mo><mfenced><mn>4</mn></mfenced><mfenced><mn>2</mn></mfenced><mfenced><mrow><mn>64</mn><mo>-</mo><mi>a</mi></mrow></mfenced></math>. Setting this expression equal to zero yields <math alttext=\"left parenthesis negative 24 right parenthesis squared minus left parenthesis 4 right parenthesis left parenthesis 2 right parenthesis left parenthesis 64 minus a right parenthesis equals 0\"><msup><mfenced><mrow><mo>-</mo><mn>24</mn></mrow></mfenced><mn>2</mn></msup><mo>-</mo><mfenced><mn>4</mn></mfenced><mfenced><mn>2</mn></mfenced><mfenced><mrow><mn>64</mn><mo>-</mo><mi>a</mi></mrow></mfenced><mo>=</mo><mn>0</mn></math>, or <math alttext=\"8 a plus 64 equals 0\"><mrow>\n\t<mrow>\n\t\t<mrow>\n\t\t\t<mn>8</mn>\n\t\t\t<mi>a</mi>\n\t\t</mrow>\n\t\t<mo>+</mo>\n\t\t<mn>64</mn>\n\t</mrow>\n\t<mo>=</mo>\n\t<mn>0</mn>\n</mrow>\n</math>. Subtracting <math alttext=\"64\"><mn>64</mn>\n</math> from both sides of this equation yields <math alttext=\"8 a equals negative 64\"><mn>8</mn><mi>a</mi><mo>=</mo><mo>-</mo><mn>64</mn></math>. Dividing both sides of this equation by <math alttext=\"8\"><mn>8</mn>\n</math> yields <math alttext=\"a equals negative 8\"><mi>a</mi><mo>=</mo><mo>-</mo><mn>8</mn></math>. Substituting <math alttext=\"negative 8\"><mo>-</mo><mn>8</mn></math> for <math alttext=\"a\"><mi>a</mi>\n</math> in the equation <math alttext=\"0 equals 2 x squared minus 24 x plus 64 minus a\"><mn>0</mn><mo>=</mo><mn>2</mn><msup><mi>x</mi><mn>2</mn></msup><mo>-</mo><mn>24</mn><mi>x</mi><mo>+</mo><mn>64</mn><mo>-</mo><mi>a</mi></math> yields <math alttext=\"0 equals 2 x squared minus 24 x plus 64 plus 8\"><mn>0</mn><mo>=</mo><mn>2</mn><msup><mi>x</mi><mn>2</mn></msup><mo>-</mo><mn>24</mn><mi>x</mi><mo>+</mo><mn>64</mn><mo>+</mo><mn>8</mn></math>, or <math alttext=\"0 equals 2 x squared minus 24 x plus 72\"><mn>0</mn><mo>=</mo><mn>2</mn><msup><mi>x</mi><mn>2</mn></msup><mo>-</mo><mn>24</mn><mi>x</mi><mo>+</mo><mn>72</mn></math>. Factoring <math alttext=\"2\"><mn>2</mn>\n</math> from the right-hand side of this equation yields <math alttext=\"0 equals 2 left parenthesis x squared minus 12 x plus 36 right parenthesis\"><mn>0</mn><mo>=</mo><mn>2</mn><mfenced><mrow><msup><mi>x</mi><mn>2</mn></msup><mo>-</mo><mn>12</mn><mi>x</mi><mo>+</mo><mn>36</mn></mrow></mfenced></math>. Dividing both sides of this equation by <math alttext=\"2\"><mn>2</mn>\n</math> yields <math alttext=\"0 equals x squared minus 12 x plus 36\"><mn>0</mn><mo>=</mo><msup><mi>x</mi><mn>2</mn></msup><mo>-</mo><mn>12</mn><mi>x</mi><mo>+</mo><mn>36</mn></math>, which is equivalent to <math alttext=\"0 equals left parenthesis x minus 6 right parenthesis left parenthesis x minus 6 right parenthesis\"><mn>0</mn><mo>=</mo><mfenced><mrow><mi>x</mi><mo>-</mo><mn>6</mn></mrow></mfenced><mfenced><mrow><mi>x</mi><mo>-</mo><mn>6</mn></mrow></mfenced></math>, or <math alttext=\"0 equals left parenthesis x minus 6 right parenthesis squared\"><mn>0</mn><mo>=</mo><msup><mfenced><mrow><mi>x</mi><mo>-</mo><mn>6</mn></mrow></mfenced><mn>2</mn></msup></math>. Taking the square root of both sides of this equation yields <math alttext=\"0 equals x minus 6\"><mrow>\n\t<mn>0</mn>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mi>x</mi>\n\t\t<mo>-</mo>\n\t\t<mn>6</mn>\n\t</mrow>\n</mrow>\n</math>. Adding <math alttext=\"6\"><mn>6</mn>\n</math> to both sides of this equation yields <math alttext=\"x equals 6\"><mrow>\n\t<mi>x</mi>\n\t<mo>=</mo>\n\t<mn>6</mn>\n</mrow>\n</math>.&nbsp;</p>\n<p>Choice A is incorrect. This is the value of <math alttext=\"a\"><mi>a</mi>\n</math>, not <math alttext=\"x\"><mi>x</mi>\n</math>.</p>\n<p>Choice B is incorrect and may result from conceptual or calculation errors.</p>\n<p>Choice D is incorrect and may result from conceptual or calculation errors.</p>","correct_answer":["C"],"has_media":false,"has_mathml":true,"has_table":false,"source_created_at":"2023-08-02T20:25:59.824000+00:00","source_updated_at":"2023-08-02T20:25:59.824000+00:00","options":[{"label":"A","content_html":"<p><math alttext=\"negative 8\"><mo>-</mo><mn>8</mn>\n</math></p>","ord":0},{"label":"B","content_html":"<p><math alttext=\"negative 6\"><mo>-</mo><mn>6</mn>\n</math></p>","ord":1},{"label":"C","content_html":"<p><math alttext=\"6\"><mn>6</mn>\n</math></p>","ord":2},{"label":"D","content_html":"<p><math alttext=\"8\"><mn>8</mn>\n</math></p>","ord":3}],"attribution":{"source_id":"cb_question_bank","source_name":"College Board digital SAT question bank (community dump)","rights_holder":"College Board","canonical_url":"https://satsuitequestionbank.collegeboard.org/","retrieved_from":"https://raw.githubusercontent.com/mdn522/sat-question-bank/main/data/cb-digital-questions.json","attribution":"SAT practice questions © College Board, from the official SAT Suite Question Bank. Retrieved via the community dump at github.com/mdn522/sat-question-bank.","disclaimer":"SAT® and PSAT/NMSQT® are trademarks registered by the College Board, which is not affiliated with, does not sponsor, and does not endorse this project.","license":"College Board copyright; source repository carries no licence. Local use only.","redistributable":false,"item_count":2017}}