{"id":"cb_question_bank:7c5ae642-edcb-4b70-b978-a8fbb6404640","source_id":"cb_question_bank","source_item_id":"7c5ae642-edcb-4b70-b978-a8fbb6404640","external_id":"30e5c8c1-d494-443c-a28f-3d8867feefed","ibn":null,"question_id":"158591f0","program":"SAT","module":"math","domain_code":"P","domain":"Advanced Math","skill_code":"P.B.","skill":"Nonlinear equations in one variable and systems of equations in two variables","difficulty":"H","score_band":6,"answer_type":"spr","answer_source":"key","layout_warning":null,"form_id":null,"module_number":null,"position":null,"stem":"x left parenthesis x plus 1 right parenthesis minus 56 equals 4 x left parenthesis x minus 7 right parenthesis What is the sum of the solutions to the given equation?","stimulus":"","stimulus_html":null,"stem_html":"<p style=\"text-align: center;\"><math alttext=\"x left parenthesis x plus 1 right parenthesis minus 56 equals 4 x left parenthesis x minus 7 right parenthesis\"><mrow>\n\t<mrow>\n\t\t<mrow>\n\t\t\t<mi>x</mi>\n\t\t\t<mfenced>\n\t\t\t\t<mrow>\n\t\t\t\t\t<mi>x</mi>\n\t\t\t\t\t<mo>+</mo>\n\t\t\t\t\t<mn>1</mn>\n\t\t\t\t</mrow>\n\t\t\t</mfenced>\n\t\t</mrow>\n\t\t<mo>-</mo>\n\t\t<mn>56</mn>\n\t</mrow>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mn>4</mn>\n\t\t<mi>x</mi>\n\t\t<mfenced>\n\t\t\t<mrow>\n\t\t\t\t<mi>x</mi>\n\t\t\t\t<mo>-</mo>\n\t\t\t\t<mn>7</mn>\n\t\t\t</mrow>\n\t\t</mfenced>\n\t</mrow>\n</mrow>\n</math></p>\n<p style=\"text-align: left;\">What is the sum of the solutions to the given equation?</p>","rationale_html":"<p style=\"text-align: left;\">The correct answer is <math alttext=\"StartFraction 29 Over 3 EndFraction\"><mfrac><mn>29</mn><mn>3</mn></mfrac></math>. Applying the distributive property to the left-hand side of the given equation,&nbsp;<math alttext=\"x left parenthesis x plus 1 right parenthesis minus 56\"><mi>x</mi><mfenced><mrow><mi>x</mi><mo>+</mo><mn>1</mn></mrow></mfenced><mo>-</mo><mn>56</mn></math>, yields <math alttext=\"x squared plus x minus 56\"><msup><mi>x</mi><mn>2</mn></msup><mo>+</mo><mi>x</mi><mo>-</mo><mn>56</mn></math>. Applying the distributive property to the right-hand side of the given equation, <math alttext=\"4 x left parenthesis x minus 7 right parenthesis\"><mn>4</mn><mi>x</mi><mfenced><mrow><mi>x</mi><mo>-</mo><mn>7</mn></mrow></mfenced></math>, yields <math alttext=\"4 x squared minus 28 x\"><mn>4</mn><msup><mi>x</mi><mn>2</mn></msup><mo>-</mo><mn>28</mn><mi>x</mi></math>. Thus, the equation becomes <math alttext=\"x squared plus x minus 56 equals 4 x squared minus 28 x\"><msup><mi>x</mi><mn>2</mn></msup><mo>+</mo><mi>x</mi><mo>-</mo><mn>56</mn><mo>=</mo><mn>4</mn><msup><mi>x</mi><mn>2</mn></msup><mo>-</mo><mn>28</mn><mi>x</mi></math>. Combining like terms on the left- and right-hand sides of this equation yields <math alttext=\"0 equals left parenthesis 4 x squared minus x squared right parenthesis plus left parenthesis minus 28 x minus x right parenthesis plus 56\"><mn>0</mn><mo>=</mo><mfenced><mrow><mn>4</mn><msup><mi>x</mi><mn>2</mn></msup><mo>-</mo><msup><mi>x</mi><mn>2</mn></msup></mrow></mfenced><mo>+</mo><mfenced><mrow><mo>-</mo><mn>28</mn><mi>x</mi><mo>-</mo><mi>x</mi></mrow></mfenced><mo>+</mo><mn>56</mn></math>, or <math alttext=\"3 x squared minus 29 x plus 56 equals 0\"><mn>3</mn><msup><mi>x</mi><mn>2</mn></msup><mo>-</mo><mn>29</mn><mi>x</mi><mo>+</mo><mn>56</mn><mo>=</mo><mn>0</mn></math>. For a quadratic equation in the form <math alttext=\"a x squared plus b x plus c equals 0\"><mi>a</mi><msup><mi>x</mi><mn>2</mn></msup><mo>+</mo><mi>b</mi><mi>x</mi><mo>+</mo><mi>c</mi><mo>=</mo><mn>0</mn></math>, where <math alttext=\"a\"><mi>a</mi>\n</math>, <math alttext=\"b\"><mi>b</mi>\n</math>, and <math alttext=\"c\"><mi>c</mi>\n</math> are constants, the quadratic formula gives the solutions to the equation in the form <math alttext=\"x equals StartFraction left parenthesis negative b plus or minus StartRoot b squared minus 4 a c EndRoot right parenthesis Over 2 a EndFraction\"><mi>x</mi><mo>=</mo><mfrac><mfenced><mrow><mo>-</mo><mi>b</mi><mo>±</mo><msqrt><msup><mi>b</mi><mn>2</mn></msup><mo>-</mo><mn>4</mn><mi>a</mi><mi>c</mi></msqrt></mrow></mfenced><mrow><mn>2</mn><mi>a</mi></mrow></mfrac></math>. Substituting <math alttext=\"3\"><mn>3</mn>\n</math> for <math alttext=\"a\"><mi>a</mi>\n</math>, <math alttext=\"negative 29\"><mo>-</mo><mn>29</mn>\n</math> for <math alttext=\"b\"><mi>b</mi>\n</math>, and <math alttext=\"56\"><mn>56</mn>\n</math> for <math alttext=\"c\"><mi>c</mi>\n</math> from the equation <math alttext=\"3 x squared minus 29 x plus 56 equals 0\"><mn>3</mn><msup><mi>x</mi><mn>2</mn></msup><mo>-</mo><mn>29</mn><mi>x</mi><mo>+</mo><mn>56</mn><mo>=</mo><mn>0</mn></math> into the quadratic formula yields&nbsp;<math alttext=\"x equals StartFraction left parenthesis 29 plus or minus StartRoot left parenthesis negative 29 right parenthesis squared minus 4 left parenthesis 3 right parenthesis left parenthesis 56 right parenthesis EndRoot right parenthesis Over 2 left parenthesis 3 right parenthesis EndFraction\"><mi>x</mi><mo>=</mo><mfrac><mfenced><mrow><mn>29</mn><mo>±</mo><msqrt><msup><mfenced><mrow><mo>-</mo><mn>29</mn></mrow></mfenced><mn>2</mn></msup><mo>-</mo><mn>4</mn><mfenced><mn>3</mn></mfenced><mfenced><mn>56</mn></mfenced></msqrt></mrow></mfenced><mrow><mn>2</mn><mfenced><mn>3</mn></mfenced></mrow></mfrac></math>, or&nbsp;<math alttext=\"x equals StartFraction 29 Over 6 EndFraction plus or minus StartFraction 13 Over 6 EndFraction\"><mi>x</mi><mo>=</mo><mfrac><mn>29</mn><mn>6</mn></mfrac><mo>±</mo><mfrac><mn>13</mn><mn>6</mn></mfrac></math>. It follows that the solutions to the given equation are&nbsp;<math alttext=\"StartFraction 29 Over 6 EndFraction plus StartFraction 13 Over 6 EndFraction\"><mfrac><mn>29</mn><mn>6</mn></mfrac><mo>+</mo><mfrac><mn>13</mn><mn>6</mn></mfrac></math> and&nbsp;<math alttext=\"StartFraction 29 Over 6 EndFraction minus StartFraction 13 Over 6 EndFraction\"><mfrac><mn>29</mn><mn>6</mn></mfrac><mo>-</mo><mfrac><mn>13</mn><mn>6</mn></mfrac></math>. Adding these two solutions gives the sum of the solutions:&nbsp;<math alttext=\"StartFraction 29 Over 6 EndFraction plus StartFraction 13 Over 6 EndFraction plus StartFraction 29 Over 6 EndFraction minus StartFraction 13 Over 6 EndFraction\"><mfrac><mn>29</mn><mn>6</mn></mfrac><mo>+</mo><mfrac><mn>13</mn><mn>6</mn></mfrac><mo>+</mo><mfrac><mn>29</mn><mn>6</mn></mfrac><mo>-</mo><mfrac><mn>13</mn><mn>6</mn></mfrac></math>, which is equivalent to&nbsp;<math alttext=\"StartFraction 29 Over 6 EndFraction plus StartFraction 29 Over 6 EndFraction\"><mfrac><mn>29</mn><mn>6</mn></mfrac><mo>+</mo><mfrac><mn>29</mn><mn>6</mn></mfrac></math>, or&nbsp;<math alttext=\"StartFraction 29 Over 3 EndFraction\"><mfrac><mn>29</mn><mn>3</mn></mfrac></math>. Note that 29/3, 9.666, and 9.667 are examples of ways to enter a correct answer.</p>","correct_answer":["29/3","9.666","9.667"],"has_media":false,"has_mathml":true,"has_table":false,"source_created_at":"2023-08-02T20:25:59.822000+00:00","source_updated_at":"2023-08-02T20:25:59.822000+00:00","options":[],"attribution":{"source_id":"cb_question_bank","source_name":"College Board digital SAT question bank (community dump)","rights_holder":"College Board","canonical_url":"https://satsuitequestionbank.collegeboard.org/","retrieved_from":"https://raw.githubusercontent.com/mdn522/sat-question-bank/main/data/cb-digital-questions.json","attribution":"SAT practice questions © College Board, from the official SAT Suite Question Bank. Retrieved via the community dump at github.com/mdn522/sat-question-bank.","disclaimer":"SAT® and PSAT/NMSQT® are trademarks registered by the College Board, which is not affiliated with, does not sponsor, and does not endorse this project.","license":"College Board copyright; source repository carries no licence. Local use only.","redistributable":false,"item_count":2017}}