{"id":"cb_question_bank:7840578a-f4f9-4538-aa77-beaf7f1cee11","source_id":"cb_question_bank","source_item_id":"7840578a-f4f9-4538-aa77-beaf7f1cee11","external_id":"f815b832-89ea-4f49-bc05-5f5c25cdb59f","ibn":null,"question_id":"87071893","program":"SAT","module":"math","domain_code":"H","domain":"Algebra","skill_code":"H.A.","skill":"Linear equations in one variable","difficulty":"E","score_band":1,"answer_type":"spr","answer_source":"key","layout_warning":null,"form_id":null,"module_number":null,"position":null,"stem":"x plus 40 equals 95 What value of x is the solution to the given equation?","stimulus":"","stimulus_html":null,"stem_html":"<p style=\"text-align: center;\"><math alttext=\"x plus 40 equals 95\"><mrow>\n\t<mrow>\n\t\t<mi>x</mi>\n\t\t<mo>+</mo>\n\t\t<mn>40</mn>\n\t</mrow>\n\t<mo>=</mo>\n\t<mn>95</mn>\n</mrow>\n</math></p>\n<p style=\"text-align: left;\">What value of <math alttext=\"x\"><mi>x</mi>\n</math> is the solution to the given equation?</p>","rationale_html":"<p>The correct answer is <math alttext=\"55\"><mn>55</mn>\n</math>. Subtracting <math alttext=\"40\"><mn>40</mn>\n</math> from both sides of the given equation yields <math alttext=\"x equals 55\"><mi>x</mi><mo>=</mo><mn>55</mn></math>. Therefore, the value of <math alttext=\"x\"><mi>x</mi>\n</math> is <math alttext=\"55\"><mn>55</mn>\n</math>.</p>","correct_answer":["55"],"has_media":false,"has_mathml":true,"has_table":false,"source_created_at":"2023-08-02T20:25:59.809000+00:00","source_updated_at":"2023-08-02T20:25:59.809000+00:00","options":[],"attribution":{"source_id":"cb_question_bank","source_name":"College Board digital SAT question bank (community dump)","rights_holder":"College Board","canonical_url":"https://satsuitequestionbank.collegeboard.org/","retrieved_from":"https://raw.githubusercontent.com/mdn522/sat-question-bank/main/data/cb-digital-questions.json","attribution":"SAT practice questions © College Board, from the official SAT Suite Question Bank. Retrieved via the community dump at github.com/mdn522/sat-question-bank.","disclaimer":"SAT® and PSAT/NMSQT® are trademarks registered by the College Board, which is not affiliated with, does not sponsor, and does not endorse this project.","license":"College Board copyright; source repository carries no licence. Local use only.","redistributable":false,"item_count":2017}}