{"id":"cb_question_bank:76f2a39c-e009-44ff-8197-3b1aefe2fafb","source_id":"cb_question_bank","source_item_id":"76f2a39c-e009-44ff-8197-3b1aefe2fafb","external_id":"ab551853-877a-4560-a1dc-8c5843c3aa42","ibn":null,"question_id":"7dbd46d9","program":"SAT","module":"math","domain_code":"P","domain":"Advanced Math","skill_code":"P.B.","skill":"Nonlinear equations in one variable and systems of equations in two variables","difficulty":"H","score_band":6,"answer_type":"mcq","answer_source":"key","layout_warning":null,"form_id":null,"module_number":null,"position":null,"stem":"8 x plus y equals negative 11 2 x squared equals y plus 341 The graphs of the equations in the given system of equations intersect at the point left parenthesis x comma y right parenthesis in the x y -plane. What is a possible value of x ?","stimulus":"","stimulus_html":null,"stem_html":"<p style=\"text-align: center;\"><math alttext=\"8 x plus y equals negative 11\"><mrow>\n\t<mrow>\n\t\t<mrow>\n\t\t\t<mn>8</mn>\n\t\t\t<mi>x</mi>\n\t\t</mrow>\n\t\t<mo>+</mo>\n\t\t<mi>y</mi>\n\t</mrow>\n\t<mo>=</mo>\n\t<mo>-</mo><mn>11</mn>\n</mrow>\n</math></p>\n<p style=\"text-align: center;\"><math alttext=\"2 x squared equals y plus 341\"><mrow>\n\t<mrow>\n\t\t<mn>2</mn>\n\t\t<msup>\n\t\t\t<mi>x</mi>\n\t\t\t<mn>2</mn>\n\t\t</msup>\n\t</mrow>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mi>y</mi>\n\t\t<mo>+</mo>\n\t\t<mn>341</mn>\n\t</mrow>\n</mrow>\n</math></p>\n<p style=\"text-align: left;\">The graphs of the equations in the given system of equations intersect at the point <math alttext=\"left parenthesis x comma y right parenthesis\"><mo>(</mo><mi>x</mi>\n<mo>,</mo><mo> </mo> <mi>y</mi>\n<mo>)</mo></math> in the <math alttext=\"x y\"><mrow>\n\t<mi>x</mi>\n\t<mi>y</mi>\n</mrow>\n</math>-plane. What is a possible value of <math alttext=\"x\"><mi>x</mi>\n</math>?</p>","rationale_html":"<p>Choice A is correct. It's given that the graphs of the equations in the given system of equations intersect at the point <math alttext=\"left parenthesis x comma y right parenthesis\"><mfenced><mrow><mi>x</mi><mo>,</mo><mi>y</mi></mrow></mfenced></math>. Therefore, this intersection point is a solution to the given system. The solution can be found by isolating <math alttext=\"y\"><mi>y</mi>\n</math> in each equation. The given equation <math alttext=\"8 x plus y equals negative 11\"><mn>8</mn><mi>x</mi><mo>+</mo><mi>y</mi><mo>=</mo><mo>-</mo><mn>11</mn></math> can be rewritten to isolate <math alttext=\"y\"><mi>y</mi>\n</math> by subtracting <math alttext=\"8 x\"><mrow>\n\t<mn>8</mn>\n\t<mi>x</mi>\n</mrow>\n</math> from both sides of the equation, which gives <math alttext=\"y equals minus 8 x minus 11\"><mi>y</mi><mo>=</mo><mo>-</mo><mn>8</mn><mi>x</mi><mo>-</mo><mn>11</mn></math>. The given equation <math alttext=\"2 x squared equals y plus 341\"><mn>2</mn><msup><mi>x</mi><mn>2</mn></msup><mo>=</mo><mi>y</mi><mo>+</mo><mn>341</mn></math> can be rewritten to isolate <math alttext=\"y\"><mi>y</mi>\n</math> by subtracting <math alttext=\"341\"><mn>341</mn>\n</math> from both sides of the equation, which gives <math alttext=\"2 x squared minus 341 equals y\"><mn>2</mn><msup><mi>x</mi><mn>2</mn></msup><mo>-</mo><mn>341</mn><mo>=</mo><mi>y</mi></math>. With each equation solved for <math alttext=\"y\"><mi>y</mi>\n</math>, the value of <math alttext=\"y\"><mi>y</mi>\n</math> from one equation can be substituted into the other, which gives <math alttext=\"2 x squared minus 341 equals minus 8 x minus 11\"><mn>2</mn><msup><mi>x</mi><mn>2</mn></msup><mo>-</mo><mn>341</mn><mo>=</mo><mo>-</mo><mn>8</mn><mi>x</mi><mo>-</mo><mn>11</mn></math>. Adding <math alttext=\"8 x\"><mrow>\n\t<mn>8</mn>\n\t<mi>x</mi>\n</mrow>\n</math> and <math alttext=\"11\"><mn>11</mn>\n</math> to both sides of this equation results in <math alttext=\"2 x squared plus 8 x minus 330 equals 0\"><mn>2</mn><msup><mi>x</mi><mn>2</mn></msup><mo>+</mo><mn>8</mn><mi>x</mi><mo>-</mo><mn>330</mn><mo>=</mo><mn>0</mn></math>. Dividing both sides of this equation by <math alttext=\"2\"><mn>2</mn>\n</math> results in <math alttext=\"x squared plus 4 x minus 165 equals 0\"><msup><mi>x</mi><mn>2</mn></msup><mo>+</mo><mn>4</mn><mi>x</mi><mo>-</mo><mn>165</mn><mo>=</mo><mn>0</mn></math>. This equation can be rewritten by factoring the left-hand side, which yields <math alttext=\"left parenthesis x plus 15 right parenthesis left parenthesis x minus 11 right parenthesis equals 0\"><mfenced><mrow><mi>x</mi><mo>+</mo><mn>15</mn></mrow></mfenced><mfenced><mrow><mi>x</mi><mo>-</mo><mn>11</mn></mrow></mfenced><mo>=</mo><mn>0</mn></math>. By the zero-product property, if <math alttext=\"left parenthesis x plus 15 right parenthesis left parenthesis x minus 11 right parenthesis equals 0\"><mfenced><mrow><mi>x</mi><mo>+</mo><mn>15</mn></mrow></mfenced><mfenced><mrow><mi>x</mi><mo>-</mo><mn>11</mn></mrow></mfenced><mo>=</mo><mn>0</mn></math>, then <math alttext=\"left parenthesis x plus 15 right parenthesis equals 0\"><mfenced><mrow><mi>x</mi><mo>+</mo><mn>15</mn></mrow></mfenced><mo>=</mo><mn>0</mn></math>, or <math alttext=\"left parenthesis x minus 11 right parenthesis equals 0\"><mfenced><mrow><mi>x</mi><mo>-</mo><mn>11</mn></mrow></mfenced><mo>=</mo><mn>0</mn></math>. It follows that <math alttext=\"x equals negative 15\"><mi>x</mi><mo>=</mo><mo>-</mo><mn>15</mn></math>, or <math alttext=\"x equals 11\"><mi>x</mi><mo>=</mo><mn>11</mn></math>. Since only <math alttext=\"negative 15\"><mo>-</mo><mn>15</mn></math> is given as a choice, a possible value of <math alttext=\"x\"><mi>x</mi>\n</math> is <math alttext=\"negative 15\"><mo>-</mo><mn>15</mn></math>.&nbsp;</p>\n<p>Choice B is incorrect and may result from conceptual or calculation errors.</p>\n<p>Choice C is incorrect and may result from conceptual or calculation errors.</p>\n<p>Choice D is incorrect and may result from conceptual or calculation errors.</p>","correct_answer":["A"],"has_media":false,"has_mathml":true,"has_table":false,"source_created_at":"2023-08-02T20:25:59.824000+00:00","source_updated_at":"2023-08-02T20:25:59.824000+00:00","options":[{"label":"A","content_html":"<p><math alttext=\"negative 15\"><mo>-</mo><mn>15</mn>\n</math></p>","ord":0},{"label":"B","content_html":"<p><math alttext=\"negative 11\"><mo>-</mo><mn>11</mn>\n</math></p>","ord":1},{"label":"C","content_html":"<p><math alttext=\"2\"><mn>2</mn>\n</math></p>","ord":2},{"label":"D","content_html":"<p><math alttext=\"8\"><mn>8</mn>\n</math></p>","ord":3}],"attribution":{"source_id":"cb_question_bank","source_name":"College Board digital SAT question bank (community dump)","rights_holder":"College Board","canonical_url":"https://satsuitequestionbank.collegeboard.org/","retrieved_from":"https://raw.githubusercontent.com/mdn522/sat-question-bank/main/data/cb-digital-questions.json","attribution":"SAT practice questions © College Board, from the official SAT Suite Question Bank. Retrieved via the community dump at github.com/mdn522/sat-question-bank.","disclaimer":"SAT® and PSAT/NMSQT® are trademarks registered by the College Board, which is not affiliated with, does not sponsor, and does not endorse this project.","license":"College Board copyright; source repository carries no licence. Local use only.","redistributable":false,"item_count":2017}}