{"id":"cb_question_bank:5d3fa538-7440-4ca9-9a59-dec2a9b0d1dc","source_id":"cb_question_bank","source_item_id":"5d3fa538-7440-4ca9-9a59-dec2a9b0d1dc","external_id":"a9c40475-9ebc-41fc-bfa0-50236b060e50","ibn":null,"question_id":"7cd1c6db","program":"SAT","module":"math","domain_code":"Q","domain":"Problem-Solving and Data Analysis","skill_code":"Q.A.","skill":"Ratios, rates, proportional relationships, and units","difficulty":"E","score_band":2,"answer_type":"mcq","answer_source":"key","layout_warning":null,"form_id":null,"module_number":null,"position":null,"stem":"An object travels at a constant speed of 12 centimeters per second. At this speed, what is the time, in seconds, that it would take for the object to travel 108 centimeters?","stimulus":"","stimulus_html":null,"stem_html":"<p style=\"text-align: left;\">An object travels at a constant speed of <math alttext=\"12\"><mn>12</mn>\n</math> centimeters per second. At this speed, what is the time, in seconds, that it would take for the object to travel <math alttext=\"108\"><mn>108</mn>\n</math> centimeters?</p>","rationale_html":"<p style=\"text-align: left;\">Choice A is correct. If the object travels <math alttext=\"108\"><mn>108</mn>\n</math> centimeters at a speed of <math alttext=\"12\"><mn>12</mn>\n</math> centimeters per second, the time of travel can be determined by dividing the total distance by the speed. This results in <math alttext=\"StartFraction 108 centimeters Over 12 centimeters slash second EndFraction\"><mfrac><mrow><mn>108</mn><mo>&nbsp;</mo><mtext>centimeters</mtext></mrow><mrow><mn>12</mn><mo>&nbsp;</mo><mtext>centimeters</mtext><mo>/</mo><mtext>second</mtext></mrow></mfrac></math>, which is <math alttext=\"9\"><mn>9</mn>\n</math> seconds.</p>\n<p style=\"text-align: left;\">Choice B is incorrect and may result from conceptual or calculation errors.</p>\n<p style=\"text-align: left;\">Choice C is incorrect and may result from conceptual or calculation errors.</p>\n<p style=\"text-align: left;\">Choice D is incorrect and may result from conceptual or calculation errors.</p>","correct_answer":["A"],"has_media":false,"has_mathml":true,"has_table":false,"source_created_at":"2023-08-02T20:25:59.829000+00:00","source_updated_at":"2023-08-02T20:25:59.829000+00:00","options":[{"label":"A","content_html":"<p><math alttext=\"9\"><mn>9</mn>\n</math></p>","ord":0},{"label":"B","content_html":"<p><math alttext=\"96\"><mn>96</mn>\n</math></p>","ord":1},{"label":"C","content_html":"<p><math alttext=\"120\"><mn>120</mn>\n</math></p>","ord":2},{"label":"D","content_html":"<p><math alttext=\"972\"><mn>972</mn>\n</math></p>","ord":3}],"attribution":{"source_id":"cb_question_bank","source_name":"College Board digital SAT question bank (community dump)","rights_holder":"College Board","canonical_url":"https://satsuitequestionbank.collegeboard.org/","retrieved_from":"https://raw.githubusercontent.com/mdn522/sat-question-bank/main/data/cb-digital-questions.json","attribution":"SAT practice questions © College Board, from the official SAT Suite Question Bank. Retrieved via the community dump at github.com/mdn522/sat-question-bank.","disclaimer":"SAT® and PSAT/NMSQT® are trademarks registered by the College Board, which is not affiliated with, does not sponsor, and does not endorse this project.","license":"College Board copyright; source repository carries no licence. Local use only.","redistributable":false,"item_count":2017}}