{"id":"cb_question_bank:4ca746b7-f356-4bf4-90dc-0ed4c1a113e9","source_id":"cb_question_bank","source_item_id":"4ca746b7-f356-4bf4-90dc-0ed4c1a113e9","external_id":"d92caabb-d558-4de0-984a-c30db0f20ddd","ibn":null,"question_id":"13e57f0a","program":"SAT","module":"math","domain_code":"P","domain":"Advanced Math","skill_code":"P.B.","skill":"Nonlinear equations in one variable and systems of equations in two variables","difficulty":"M","score_band":4,"answer_type":"mcq","answer_source":"key","layout_warning":null,"form_id":null,"module_number":null,"position":null,"stem":"minus 4 x squared minus 7 x equals negative 36 What is the positive solution to the given equation?","stimulus":"","stimulus_html":null,"stem_html":"<p style=\"text-align: center;\"><math alttext=\"minus 4 x squared minus 7 x equals negative 36\"><mrow>\n\t<mrow>\n\t\t<mrow>\n\t\t\t<mo>-</mo>\n\t\t\t<mn>4</mn>\n\t\t\t<msup>\n\t\t\t\t<mi>x</mi>\n\t\t\t\t<mn>2</mn>\n\t\t\t</msup>\n\t\t</mrow>\n\t\t<mo>-</mo>\n\t\t<mrow>\n\t\t\t<mn>7</mn>\n\t\t\t<mi>x</mi>\n\t\t</mrow>\n\t</mrow>\n\t<mo>=</mo>\n\t<mo>-</mo><mn>36</mn>\n</mrow>\n</math></p>\n<p style=\"text-align: left;\">What is the positive solution to the given equation?</p>","rationale_html":"<p style=\"text-align: left;\">Choice B is correct. Multiplying each side of the given equation by <math alttext=\"negative 16\"><mo>-</mo><mn>16</mn>\n</math> yields <math alttext=\"64 x squared plus 112 x equals 576\"><mrow>\n\t<mrow>\n\t\t<mrow>\n\t\t\t<mn>64</mn>\n\t\t\t<msup>\n\t\t\t\t<mi>x</mi>\n\t\t\t\t<mn>2</mn>\n\t\t\t</msup>\n\t\t</mrow>\n\t\t<mo>+</mo>\n\t\t<mrow>\n\t\t\t<mn>112</mn>\n\t\t\t<mi>x</mi>\n\t\t</mrow>\n\t</mrow>\n\t<mo>=</mo>\n\t<mn>576</mn>\n</mrow>\n</math>. To complete the square, adding <math alttext=\"49\"><mn>49</mn>\n</math> to each side of this equation yields&nbsp;<math alttext=\"64 x squared plus 112 x plus 49 equals 576 plus 49\"><mn>64</mn><msup><mi>x</mi><mn>2</mn></msup><mo>+</mo><mn>112</mn><mi>x</mi><mo>+</mo><mn>49</mn><mo>=</mo><mn>576</mn><mo>+</mo><mn>49</mn></math>, or&nbsp;<math alttext=\"left parenthesis 8 x plus 7 right parenthesis squared equals 625\"><msup><mfenced><mrow><mn>8</mn><mi>x</mi><mo>+</mo><mn>7</mn></mrow></mfenced><mn>2</mn></msup><mo>=</mo><mn>625</mn></math>. Taking the square root of each side of this equation yields two equations: <math alttext=\"8 x plus 7 equals 25\"><mrow>\n\t<mrow>\n\t\t<mrow>\n\t\t\t<mn>8</mn>\n\t\t\t<mi>x</mi>\n\t\t</mrow>\n\t\t<mo>+</mo>\n\t\t<mn>7</mn>\n\t</mrow>\n\t<mo>=</mo>\n\t<mn>25</mn>\n</mrow>\n</math> and <math alttext=\"8 x plus 7 equals negative 25\"><mrow>\n\t<mrow>\n\t\t<mrow>\n\t\t\t<mn>8</mn>\n\t\t\t<mi>x</mi>\n\t\t</mrow>\n\t\t<mo>+</mo>\n\t\t<mn>7</mn>\n\t</mrow>\n\t<mo>=</mo>\n\t<mo>-</mo><mn>25</mn>\n</mrow>\n</math>. Subtracting <math alttext=\"7\"><mn>7</mn>\n</math> from each side of the equation <math alttext=\"8 x plus 7 equals 25\"><mrow>\n\t<mrow>\n\t\t<mrow>\n\t\t\t<mn>8</mn>\n\t\t\t<mi>x</mi>\n\t\t</mrow>\n\t\t<mo>+</mo>\n\t\t<mn>7</mn>\n\t</mrow>\n\t<mo>=</mo>\n\t<mn>25</mn>\n</mrow>\n</math> yields <math alttext=\"8 x equals 18\"><mrow>\n\t<mrow>\n\t\t<mn>8</mn>\n\t\t<mi>x</mi>\n\t</mrow>\n\t<mo>=</mo>\n\t<mn>18</mn>\n</mrow>\n</math>. Dividing each side of this equation by <math alttext=\"8\"><mn>8</mn>\n</math> yields&nbsp;<math alttext=\"x equals StartFraction 18 Over 8 EndFraction\"><mi>x</mi><mo>=</mo><mfrac><mn>18</mn><mn>8</mn></mfrac></math>, or <math alttext=\"x equals nine fourths\"><mrow>\n\t<mi>x</mi>\n\t<mo>=</mo>\n\t<mfrac>\n\t\t<mn>9</mn>\n\t\t<mn>4</mn>\n\t</mfrac>\n</mrow>\n</math>. Therefore, <math alttext=\"nine fourths\"><mfrac>\n\t<mn>9</mn>\n\t<mn>4</mn>\n</mfrac>\n</math> is a solution to the given equation. Subtracting <math alttext=\"7\"><mn>7</mn>\n</math> from each side of the equation <math alttext=\"8 x plus 7 equals negative 25\"><mrow>\n\t<mrow>\n\t\t<mrow>\n\t\t\t<mn>8</mn>\n\t\t\t<mi>x</mi>\n\t\t</mrow>\n\t\t<mo>+</mo>\n\t\t<mn>7</mn>\n\t</mrow>\n\t<mo>=</mo>\n\t<mo>-</mo><mn>25</mn>\n</mrow>\n</math> yields <math alttext=\"8 x equals negative 32\"><mrow>\n\t<mrow>\n\t\t<mn>8</mn>\n\t\t<mi>x</mi>\n\t</mrow>\n\t<mo>=</mo>\n\t<mo>-</mo><mn>32</mn>\n</mrow>\n</math>. Dividing each side of this equation by <math alttext=\"8\"><mn>8</mn>\n</math> yields <math alttext=\"x equals negative 4\"><mrow>\n\t<mi>x</mi>\n\t<mo>=</mo>\n\t<mo>-</mo><mn>4</mn>\n</mrow>\n</math>. Therefore, the given equation has two solutions, <math alttext=\"nine fourths\"><mfrac>\n\t<mn>9</mn>\n\t<mn>4</mn>\n</mfrac>\n</math> and <math alttext=\"negative 4\"><mo>-</mo><mn>4</mn>\n</math>. Since <math alttext=\"nine fourths\"><mfrac>\n\t<mn>9</mn>\n\t<mn>4</mn>\n</mfrac>\n</math> is positive, it follows that <math alttext=\"nine fourths\"><mfrac>\n\t<mn>9</mn>\n\t<mn>4</mn>\n</mfrac>\n</math> is the positive solution to the given equation.</p>\n<p style=\"text-align: left;\">Alternate approach: Adding <math alttext=\"4 x squared\"><mrow>\n\t<mn>4</mn>\n\t<msup>\n\t\t<mi>x</mi>\n\t\t<mn>2</mn>\n\t</msup>\n</mrow>\n</math> and <math alttext=\"7 x\"><mrow>\n\t<mn>7</mn>\n\t<mi>x</mi>\n</mrow>\n</math> to each side of the given equation yields <math alttext=\"0 equals 4 x squared plus 7 x minus 36\"><mrow>\n\t<mn>0</mn>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mrow>\n\t\t\t<mn>4</mn>\n\t\t\t<msup>\n\t\t\t\t<mi>x</mi>\n\t\t\t\t<mn>2</mn>\n\t\t\t</msup>\n\t\t</mrow>\n\t\t<mo>+</mo>\n\t\t<mrow>\n\t\t\t<mn>7</mn>\n\t\t\t<mi>x</mi>\n\t\t</mrow>\n\t\t<mo>-</mo>\n\t\t<mn>36</mn>\n\t</mrow>\n</mrow>\n</math>. The right-hand side of this equation can be rewritten as <math alttext=\"4 x squared plus 16 x minus 9 x minus 36\"><mn>4</mn><msup><mi>x</mi><mn>2</mn></msup><mo>+</mo><mn>16</mn><mi>x</mi><mo>-</mo><mn>9</mn><mi>x</mi><mo>-</mo><mn>36</mn></math>. Factoring out the common factor of <math alttext=\"4 x\"><mrow>\n\t<mn>4</mn>\n\t<mi>x</mi>\n</mrow>\n</math> from the first two terms of this expression and the common factor of <math alttext=\"negative 9\"><mo>-</mo><mn>9</mn>\n</math> from the second two terms yields <math alttext=\"4 x left parenthesis x plus 4 right parenthesis minus 9 left parenthesis x plus 4 right parenthesis\"><mn>4</mn><mi>x</mi><mfenced><mrow><mi>x</mi><mo>+</mo><mn>4</mn></mrow></mfenced><mo>-</mo><mn>9</mn><mfenced><mrow><mi>x</mi><mo>+</mo><mn>4</mn></mrow></mfenced></math>. Factoring out the common factor of&nbsp;<math alttext=\"left parenthesis x plus 4 right parenthesis\"><mfenced><mrow><mi>x</mi><mo>+</mo><mn>4</mn></mrow></mfenced></math> from these two terms yields the expression&nbsp;<math alttext=\"left parenthesis 4 x minus 9 right parenthesis left parenthesis x plus 4 right parenthesis\"><mfenced><mrow><mn>4</mn><mi>x</mi><mo>-</mo><mn>9</mn></mrow></mfenced><mfenced><mrow><mi>x</mi><mo>+</mo><mn>4</mn></mrow></mfenced></math>. Since this expression is equal to <math alttext=\"0\"><mn>0</mn>\n</math>, it follows that either <math alttext=\"4 x minus 9 equals 0\"><mrow>\n\t<mrow>\n\t\t<mrow>\n\t\t\t<mn>4</mn>\n\t\t\t<mi>x</mi>\n\t\t</mrow>\n\t\t<mo>-</mo>\n\t\t<mn>9</mn>\n\t</mrow>\n\t<mo>=</mo>\n\t<mn>0</mn>\n</mrow>\n</math> or <math alttext=\"x plus 4 equals 0\"><mrow>\n\t<mrow>\n\t\t<mi>x</mi>\n\t\t<mo>+</mo>\n\t\t<mn>4</mn>\n\t</mrow>\n\t<mo>=</mo>\n\t<mn>0</mn>\n</mrow>\n</math>. Adding <math alttext=\"9\"><mn>9</mn>\n</math> to each side of the equation <math alttext=\"4 x minus 9 equals 0\"><mrow>\n\t<mrow>\n\t\t<mrow>\n\t\t\t<mn>4</mn>\n\t\t\t<mi>x</mi>\n\t\t</mrow>\n\t\t<mo>-</mo>\n\t\t<mn>9</mn>\n\t</mrow>\n\t<mo>=</mo>\n\t<mn>0</mn>\n</mrow>\n</math> yields <math alttext=\"4 x equals 9\"><mrow>\n\t<mrow>\n\t\t<mn>4</mn>\n\t\t<mi>x</mi>\n\t</mrow>\n\t<mo>=</mo>\n\t<mn>9</mn>\n</mrow>\n</math>. Dividing each side of this equation by <math alttext=\"4\"><mn>4</mn>\n</math> yields <math alttext=\"x equals nine fourths\"><mrow>\n\t<mi>x</mi>\n\t<mo>=</mo>\n\t<mfrac>\n\t\t<mn>9</mn>\n\t\t<mn>4</mn>\n\t</mfrac>\n</mrow>\n</math>. Therefore, <math alttext=\"nine fourths\"><mfrac>\n\t<mn>9</mn>\n\t<mn>4</mn>\n</mfrac>\n</math> is a positive solution to the given equation. Subtracting <math alttext=\"4\"><mn>4</mn>\n</math> from each side of the equation <math alttext=\"x plus 4 equals 0\"><mrow>\n\t<mrow>\n\t\t<mi>x</mi>\n\t\t<mo>+</mo>\n\t\t<mn>4</mn>\n\t</mrow>\n\t<mo>=</mo>\n\t<mn>0</mn>\n</mrow>\n</math> yields <math alttext=\"x equals negative 4\"><mrow>\n\t<mi>x</mi>\n\t<mo>=</mo>\n\t<mo>-</mo><mn>4</mn>\n</mrow>\n</math>. Therefore, the given equation has two solutions, <math alttext=\"nine fourths\"><mfrac>\n\t<mn>9</mn>\n\t<mn>4</mn>\n</mfrac>\n</math> and <math alttext=\"negative 4\"><mo>-</mo><mn>4</mn>\n</math>. Since <math alttext=\"nine fourths\"><mfrac>\n\t<mn>9</mn>\n\t<mn>4</mn>\n</mfrac>\n</math> is positive, it follows that <math alttext=\"nine fourths\"><mfrac>\n\t<mn>9</mn>\n\t<mn>4</mn>\n</mfrac>\n</math> is the positive solution to the given equation.</p>\n<p style=\"text-align: left;\">Choice A is incorrect. Substituting <math alttext=\"seven fourths\"><mfrac>\n\t<mn>7</mn>\n\t<mn>4</mn>\n</mfrac>\n</math> for <math alttext=\"x\"><mi>x</mi>\n</math> in the given equation yields&nbsp;<math alttext=\"negative StartFraction 49 Over 2 EndFraction equals negative 36\"><mo>-</mo><mfrac><mn>49</mn><mn>2</mn></mfrac><mo>=</mo><mo>-</mo><mn>36</mn></math>, which is false.</p>\n<p style=\"text-align: left;\">Choice C is incorrect. Substituting <math alttext=\"4\"><mn>4</mn>\n</math> for <math alttext=\"x\"><mi>x</mi>\n</math> in the given equation yields&nbsp;<math alttext=\"negative 92 equals negative 36\"><mo>-</mo><mn>92</mn><mo>=</mo><mo>-</mo><mn>36</mn></math>, which is false.</p>\n<p style=\"text-align: left;\">Choice D is incorrect. Substituting <math alttext=\"7\"><mn>7</mn>\n</math> for <math alttext=\"x\"><mi>x</mi>\n</math> in the given equation yields&nbsp;<math alttext=\"negative 245 equals negative 36\"><mo>-</mo><mn>245</mn><mo>=</mo><mo>-</mo><mn>36</mn></math>, which is false.</p>","correct_answer":["B"],"has_media":false,"has_mathml":true,"has_table":false,"source_created_at":"2023-08-02T20:25:59.825000+00:00","source_updated_at":"2023-08-02T20:25:59.825000+00:00","options":[{"label":"A","content_html":"<p><math alttext=\"seven fourths\"><mfrac>\n\t<mn>7</mn>\n\t<mn>4</mn>\n</mfrac>\n</math></p>","ord":0},{"label":"B","content_html":"<p><math alttext=\"nine fourths\"><mfrac>\n\t<mn>9</mn>\n\t<mn>4</mn>\n</mfrac>\n</math></p>","ord":1},{"label":"C","content_html":"<p><math alttext=\"4\"><mn>4</mn>\n</math></p>","ord":2},{"label":"D","content_html":"<p><math alttext=\"7\"><mn>7</mn>\n</math></p>","ord":3}],"attribution":{"source_id":"cb_question_bank","source_name":"College Board digital SAT question bank (community dump)","rights_holder":"College Board","canonical_url":"https://satsuitequestionbank.collegeboard.org/","retrieved_from":"https://raw.githubusercontent.com/mdn522/sat-question-bank/main/data/cb-digital-questions.json","attribution":"SAT practice questions © College Board, from the official SAT Suite Question Bank. Retrieved via the community dump at github.com/mdn522/sat-question-bank.","disclaimer":"SAT® and PSAT/NMSQT® are trademarks registered by the College Board, which is not affiliated with, does not sponsor, and does not endorse this project.","license":"College Board copyright; source repository carries no licence. Local use only.","redistributable":false,"item_count":2017}}