{"id":"cb_question_bank:224e737b-b611-442b-af26-ef476da15a5b","source_id":"cb_question_bank","source_item_id":"224e737b-b611-442b-af26-ef476da15a5b","external_id":"c1c7e4d7-d6dc-4e54-8b49-cbd88eab7153","ibn":null,"question_id":"a07ed090","program":"SAT","module":"math","domain_code":"S","domain":"Geometry and Trigonometry","skill_code":"S.A.","skill":"Area and volume","difficulty":"H","score_band":6,"answer_type":"mcq","answer_source":"key","layout_warning":null,"form_id":null,"module_number":null,"position":null,"stem":"The figure shown is a right circular cylinder with a radius of r and height of h . A second right circular cylinder (not shown) has a volume that is 392 times as large as the volume of the cylinder shown. Which of the following could represent the radius upper R , in terms of r , and the height upper H , in terms of h , of the second cylinder?","stimulus":"","stimulus_html":null,"stem_html":"<p style=\"text-align: center;\"></p><figure class=\"image\"><svg xmlns=\"http://www.w3.org/2000/svg\" width=\"160.028\" height=\"125.958\" viewBox=\"0 0 160.028 125.958\"><g id=\"b1939c66-ebf5-4ce0-828a-3cbd3c919788\"><ellipse cx=\"72.747\" cy=\"25.442\" rx=\"71.802\" ry=\"24.497\" fill=\"none\" stroke=\"#231f20\" stroke-width=\"1.89\"></ellipse><path d=\"M.945,26.742v70.7c0,15.227,32.147,27.571,71.8,27.571s71.8-12.344,71.8-27.571v-72\" fill=\"none\" stroke=\"#231f20\" stroke-width=\"1.89\"></path><circle cx=\"72.747\" cy=\"25.442\" r=\"3.78\" fill=\"#231f20\"></circle><line x1=\"72.747\" y1=\"25.442\" x2=\"106.539\" y2=\"3.823\" stroke=\"#231f20\" stroke-width=\"1.89\"></line><path d=\"M94.537,16.626a5.691,5.691,0,0,1,2.779-1.946c.5,0,.516.914.218,2.3l-.2.992h.06c1.012-1.945,2.183-3.3,2.977-3.3a1.074,1.074,0,0,1,.854.5.871.871,0,0,1-.02.853,2.074,2.074,0,0,1-.516.575c-.179.119-.338.119-.437.021a.92.92,0,0,0-.675-.338c-.238,0-.556.2-1.013.834a13.7,13.7,0,0,0-1.409,2.462c-.318,1.33-.556,2.58-.794,3.89a7.34,7.34,0,0,0-1.409.358l-.159-.159c.516-2.124,1.072-4.566,1.449-6.69.119-.655.119-.853-.04-.853a3.927,3.927,0,0,0-1.409.952Z\" fill=\"#231f20\"></path><path d=\"M160.028,68.392a5.167,5.167,0,0,1-2.859,1.907c-.516,0-.655-.556-.337-1.926l1.051-4.606c.239-1.051.16-1.409-.158-1.409-.913,0-3.236,2.223-4.209,3.95-.2.873-.555,2.641-.734,3.614a8.517,8.517,0,0,0-1.409.377l-.14-.16c.854-3.831,1.728-7.84,2.5-11.911.218-1.032.119-1.092-.655-1.111l-.577-.02.06-.476a18.687,18.687,0,0,0,2.919-.7c.179,0,.2.159.079.7l-1.787,8.238h.04a11.663,11.663,0,0,1,3.673-3.295,2.966,2.966,0,0,1,1.33-.417c.5,0,1.052.358.556,2.521l-1.033,4.447c-.119.575-.1.715.06.715a3.454,3.454,0,0,0,1.37-.913Z\" fill=\"#231f20\"></path></g></svg></figure><p></p>\n<p style=\"text-align: left;\">The figure shown is a right circular cylinder with a radius of <math alttext=\"r\"><mi>r</mi>\n</math> and height of <math alttext=\"h\"><mi>h</mi>\n</math>. A second right circular cylinder (not shown) has a volume that is <math alttext=\"392\"><mn>392</mn>\n</math> times as large as the volume of the cylinder shown. Which of the following could represent the radius <math alttext=\"upper R\"><mi>R</mi>\n</math>, in terms of <math alttext=\"r\"><mi>r</mi>\n</math>, and the height <math alttext=\"upper H\"><mi>H</mi>\n</math>, in terms of <math alttext=\"h\"><mi>h</mi>\n</math>, of the second cylinder?</p>","rationale_html":"<p style=\"text-align: left;\">Choice C is correct. The volume of a right circular cylinder is equal to <math alttext=\"pi a squared b\"><mi>π</mi><msup><mi>a</mi><mn>2</mn></msup><mi>b</mi></math>, where <math alttext=\"a\"><mi>a</mi>\n</math> is the radius of a base of the cylinder and <math alttext=\"b\"><mi>b</mi>\n</math> is the height of the cylinder. It’s given that the cylinder shown has a radius of <math alttext=\"r\"><mi>r</mi>\n</math> and a height of <math alttext=\"h\"><mi>h</mi>\n</math>. It follows that the volume of the cylinder shown is equal to <math alttext=\"pi r squared h\"><mi>π</mi><msup><mi>r</mi><mn>2</mn></msup><mi>h</mi></math>. It’s given that the second right circular cylinder has a radius of <math alttext=\"upper R\"><mi>R</mi>\n</math> and a height of <math alttext=\"upper H\"><mi>H</mi>\n</math>. It follows that the volume of the second cylinder is equal to <math alttext=\"pi upper R squared upper H\"><mi>π</mi><msup><mi>R</mi><mn>2</mn></msup><mi>H</mi></math>. Choice C gives <math alttext=\"upper R equals 7 r\"><mrow>\n\t<mi>R</mi>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mn>7</mn>\n\t\t<mi>r</mi>\n\t</mrow>\n</mrow>\n</math> and <math alttext=\"upper H equals 8 h\"><mrow>\n\t<mi>H</mi>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mn>8</mn>\n\t\t<mi>h</mi>\n\t</mrow>\n</mrow>\n</math>. Substituting <math alttext=\"7 r\"><mrow>\n\t<mn>7</mn>\n\t<mi>r</mi>\n</mrow>\n</math> for <math alttext=\"upper R\"><mi>R</mi>\n</math> and <math alttext=\"8 h\"><mrow>\n\t<mn>8</mn>\n\t<mi>h</mi>\n</mrow>\n</math> for <math alttext=\"upper H\"><mi>H</mi>\n</math> in the expression that represents the volume of the second cylinder yields <math alttext=\"pi left parenthesis 7 r right parenthesis squared left parenthesis 8 h right parenthesis\"><mi>π</mi><msup><mfenced><mrow><mn>7</mn><mi>r</mi></mrow></mfenced><mn>2</mn></msup><mfenced><mrow><mn>8</mn><mi>h</mi></mrow></mfenced></math>, or <math alttext=\"pi left parenthesis 49 r squared right parenthesis left parenthesis 8 h right parenthesis\"><mi>π</mi><mfenced><mrow><mn>49</mn><msup><mi>r</mi><mn>2</mn></msup></mrow></mfenced><mfenced><mrow><mn>8</mn><mi>h</mi></mrow></mfenced></math>, which is equivalent to <math alttext=\"pi left parenthesis 392 r squared h right parenthesis\"><mi>π</mi><mfenced><mrow><mn>392</mn><msup><mi>r</mi><mn>2</mn></msup><mi>h</mi></mrow></mfenced></math>, or <math alttext=\"392 left parenthesis pi r squared h right parenthesis\"><mn>392</mn><mfenced><mrow><mi>π</mi><msup><mi>r</mi><mn>2</mn></msup><mi>h</mi></mrow></mfenced></math>. This expression is equal to <math alttext=\"392\"><mn>392</mn>\n</math> times the volume of the cylinder shown, <math alttext=\"pi r squared h\"><mi>π</mi><msup><mi>r</mi><mn>2</mn></msup><mi>h</mi></math>. Therefore, <math alttext=\"upper R equals 7 r\"><mrow>\n\t<mi>R</mi>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mn>7</mn>\n\t\t<mi>r</mi>\n\t</mrow>\n</mrow>\n</math> and <math alttext=\"upper H equals 8 h\"><mrow>\n\t<mi>H</mi>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mn>8</mn>\n\t\t<mi>h</mi>\n\t</mrow>\n</mrow>\n</math> could represent the radius <math alttext=\"upper R\"><mi>R</mi>\n</math>, in terms of <math alttext=\"r\"><mi>r</mi>\n</math>, and the height <math alttext=\"upper H\"><mi>H</mi>\n</math>, in terms of <math alttext=\"h\"><mi>h</mi>\n</math>, of the second cylinder.</p>\n<p style=\"text-align: left;\">Choice A is incorrect. Substituting <math alttext=\"8 r\"><mrow>\n\t<mn>8</mn>\n\t<mi>r</mi>\n</mrow>\n</math> for <math alttext=\"upper R\"><mi>R</mi>\n</math> and <math alttext=\"7 h\"><mrow>\n\t<mn>7</mn>\n\t<mi>h</mi>\n</mrow>\n</math> for <math alttext=\"upper H\"><mi>H</mi>\n</math> in the expression that represents the volume of the second cylinder yields <math alttext=\"pi left parenthesis 8 r right parenthesis squared left parenthesis 7 h right parenthesis\"><mi>π</mi><msup><mfenced><mrow><mn>8</mn><mi>r</mi></mrow></mfenced><mn>2</mn></msup><mfenced><mrow><mn>7</mn><mi>h</mi></mrow></mfenced></math>, or <math alttext=\"pi left parenthesis 64 r squared right parenthesis left parenthesis 7 h right parenthesis\"><mi>π</mi><mfenced><mrow><mn>64</mn><msup><mi>r</mi><mn>2</mn></msup></mrow></mfenced><mfenced><mrow><mn>7</mn><mi>h</mi></mrow></mfenced></math>, which is equivalent to <math alttext=\"pi left parenthesis 448 r squared h right parenthesis\"><mi>π</mi><mfenced><mrow><mn>448</mn><msup><mi>r</mi><mn>2</mn></msup><mi>h</mi></mrow></mfenced></math>, or <math alttext=\"448 left parenthesis pi r squared h right parenthesis\"><mn>448</mn><mfenced><mrow><mi>π</mi><msup><mi>r</mi><mn>2</mn></msup><mi>h</mi></mrow></mfenced></math>. This expression is equal to <math alttext=\"448\"><mn>448</mn>\n</math>, not <math alttext=\"392\"><mn>392</mn>\n</math>, times the volume of the cylinder shown.&nbsp;</p>\n<p>Choice B is incorrect. Substituting <math alttext=\"8 r\"><mrow>\n\t<mn>8</mn>\n\t<mi>r</mi>\n</mrow>\n</math> for <math alttext=\"upper R\"><mi>R</mi>\n</math> and <math alttext=\"49 h\"><mrow>\n\t<mn>49</mn>\n\t<mi>h</mi>\n</mrow>\n</math> for <math alttext=\"upper H\"><mi>H</mi>\n</math> in the expression that represents the volume of the second cylinder yields <math alttext=\"pi left parenthesis 8 r right parenthesis squared left parenthesis 49 h right parenthesis\"><mi>π</mi><msup><mfenced><mrow><mn>8</mn><mi>r</mi></mrow></mfenced><mn>2</mn></msup><mfenced><mrow><mn>49</mn><mi>h</mi></mrow></mfenced></math>, or <math alttext=\"pi left parenthesis 64 r squared right parenthesis left parenthesis 49 h right parenthesis\"><mi>π</mi><mfenced><mrow><mn>64</mn><msup><mi>r</mi><mn>2</mn></msup></mrow></mfenced><mfenced><mrow><mn>49</mn><mi>h</mi></mrow></mfenced></math>, which is equivalent to <math alttext=\"pi left parenthesis 3,136 r squared h right parenthesis\"><mi>π</mi><mfenced><mrow><mn>3,136</mn><msup><mi>r</mi><mn>2</mn></msup><mi>h</mi></mrow></mfenced></math>, or <math alttext=\"3,136 left parenthesis pi r squared h right parenthesis\"><mn>3,136</mn><mfenced><mrow><mi>π</mi><msup><mi>r</mi><mn>2</mn></msup><mi>h</mi></mrow></mfenced></math>. This expression is equal to <math alttext=\"3,136\"><mn>3,136</mn>\n</math>, not <math alttext=\"392\"><mn>392</mn>\n</math>, times the volume of the cylinder shown.</p>\n<p style=\"text-align: left;\">Choice D is incorrect. Substituting <math alttext=\"49 r\"><mrow>\n\t<mn>49</mn>\n\t<mi>r</mi>\n</mrow>\n</math> for <math alttext=\"upper R\"><mi>R</mi>\n</math> and <math alttext=\"8 h\"><mrow>\n\t<mn>8</mn>\n\t<mi>h</mi>\n</mrow>\n</math> for <math alttext=\"upper H\"><mi>H</mi>\n</math> in the expression that represents the volume of the second cylinder yields <math alttext=\"pi left parenthesis 49 r right parenthesis squared left parenthesis 8 h right parenthesis\"><mi>π</mi><msup><mfenced><mrow><mn>49</mn><mi>r</mi></mrow></mfenced><mn>2</mn></msup><mfenced><mrow><mn>8</mn><mi>h</mi></mrow></mfenced></math>, or <math alttext=\"pi left parenthesis 2,401 r squared right parenthesis left parenthesis 8 h right parenthesis\"><mi>π</mi><mfenced><mrow><mn>2,401</mn><msup><mi>r</mi><mn>2</mn></msup></mrow></mfenced><mfenced><mrow><mn>8</mn><mi>h</mi></mrow></mfenced></math>, which is equivalent to <math alttext=\"pi left parenthesis 19,208 r squared h right parenthesis\"><mi>π</mi><mfenced><mrow><mn>19,208</mn><msup><mi>r</mi><mn>2</mn></msup><mi>h</mi></mrow></mfenced></math>, or <math alttext=\"19,208 left parenthesis pi r squared h right parenthesis\"><mn>19,208</mn><mfenced><mrow><mi>π</mi><msup><mi>r</mi><mn>2</mn></msup><mi>h</mi></mrow></mfenced></math>. This expression is equal to <math alttext=\"19,208\"><mn>19,208</mn>\n</math>, not <math alttext=\"392\"><mn>392</mn>\n</math>, times the volume of the cylinder shown.</p>","correct_answer":["C"],"has_media":true,"has_mathml":true,"has_table":false,"source_created_at":"2023-08-02T20:25:59.837000+00:00","source_updated_at":"2023-08-02T20:25:59.837000+00:00","options":[{"label":"A","content_html":"<p><math alttext=\"upper R equals 8 r\"><mrow>\n\t<mi>R</mi>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mn>8</mn>\n\t\t<mi>r</mi>\n\t</mrow>\n</mrow>\n</math> and <math alttext=\"upper H equals 7 h\"><mrow>\n\t<mi>H</mi>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mn>7</mn>\n\t\t<mi>h</mi>\n\t</mrow>\n</mrow>\n</math></p>","ord":0},{"label":"B","content_html":"<p><math alttext=\"upper R equals 8 r\"><mrow>\n\t<mi>R</mi>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mn>8</mn>\n\t\t<mi>r</mi>\n\t</mrow>\n</mrow>\n</math> and <math alttext=\"upper H equals 49 h\"><mrow>\n\t<mi>H</mi>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mn>49</mn>\n\t\t<mi>h</mi>\n\t</mrow>\n</mrow>\n</math></p>","ord":1},{"label":"C","content_html":"<p><math alttext=\"upper R equals 7 r\"><mrow>\n\t<mi>R</mi>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mn>7</mn>\n\t\t<mi>r</mi>\n\t</mrow>\n</mrow>\n</math> and <math alttext=\"upper H equals 8 h\"><mrow>\n\t<mi>H</mi>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mn>8</mn>\n\t\t<mi>h</mi>\n\t</mrow>\n</mrow>\n</math></p>","ord":2},{"label":"D","content_html":"<p><math alttext=\"upper R equals 49 r\"><mrow>\n\t<mi>R</mi>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mn>49</mn>\n\t\t<mi>r</mi>\n\t</mrow>\n</mrow>\n</math> and <math alttext=\"upper H equals 8 h\"><mrow>\n\t<mi>H</mi>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mn>8</mn>\n\t\t<mi>h</mi>\n\t</mrow>\n</mrow>\n</math></p>","ord":3}],"attribution":{"source_id":"cb_question_bank","source_name":"College Board digital SAT question bank (community dump)","rights_holder":"College Board","canonical_url":"https://satsuitequestionbank.collegeboard.org/","retrieved_from":"https://raw.githubusercontent.com/mdn522/sat-question-bank/main/data/cb-digital-questions.json","attribution":"SAT practice questions © College Board, from the official SAT Suite Question Bank. Retrieved via the community dump at github.com/mdn522/sat-question-bank.","disclaimer":"SAT® and PSAT/NMSQT® are trademarks registered by the College Board, which is not affiliated with, does not sponsor, and does not endorse this project.","license":"College Board copyright; source repository carries no licence. Local use only.","redistributable":false,"item_count":2017}}