{"id":"cb_question_bank:20c2550c-c0bf-4676-b826-93010aee054c","source_id":"cb_question_bank","source_item_id":"20c2550c-c0bf-4676-b826-93010aee054c","external_id":"bf8e1345-911b-42f4-ad9c-688a5ce90cb6","ibn":null,"question_id":"7902bed0","program":"SAT","module":"math","domain_code":"P","domain":"Advanced Math","skill_code":"P.C.","skill":"Nonlinear functions","difficulty":"H","score_band":6,"answer_type":"mcq","answer_source":"key","layout_warning":null,"form_id":null,"module_number":null,"position":null,"stem":"A machine launches a softball from ground level. The softball reaches a maximum height of 51.84 meters above the ground at 1.8 seconds and hits the ground at 3.6 seconds. Which equation represents the height above ground h , in meters, of the softball t seconds after it is launched?","stimulus":"","stimulus_html":null,"stem_html":"<p style=\"text-align: left;\">A machine launches a softball from ground level. The softball reaches a maximum height of <math alttext=\"51.84\"><mn>51.84</mn>\n</math> meters above the ground at <math alttext=\"1.8\"><mn>1.8</mn>\n</math> seconds and hits the ground at <math alttext=\"3.6\"><mn>3.6</mn>\n</math> seconds. Which equation represents the height above ground <math alttext=\"h\"><mi>h</mi>\n</math>, in meters, of the softball <math alttext=\"t\"><mi>t</mi>\n</math> seconds after it is launched?</p>","rationale_html":"<p style=\"text-align: left;\">Choice D is correct. An equation representing the height above ground <math alttext=\"h\"><mi>h</mi>\n</math>, in meters, of a softball <math alttext=\"t\"><mi>t</mi>\n</math> seconds after it is launched by a machine from ground level can be written in the form <math alttext=\"h equals minus a left parenthesis t minus b right parenthesis squared plus c\"><mi>h</mi><mo>=</mo><mo>-</mo><mi>a</mi><msup><mfenced><mrow><mi>t</mi><mo>-</mo><mi>b</mi></mrow></mfenced><mn>2</mn></msup><mo>+</mo><mi>c</mi></math>, where <math alttext=\"a\"><mi>a</mi>\n</math>, <math alttext=\"b\"><mi>b</mi>\n</math>, and <math alttext=\"c\"><mi>c</mi>\n</math> are positive constants. In this equation, <math alttext=\"b\"><mi>b</mi>\n</math> represents the time, in seconds, at which the softball reaches its maximum height of <math alttext=\"c\"><mi>c</mi>\n</math> meters above the ground. It's given that this softball reaches a maximum height of <math alttext=\"51.84\"><mn>51.84</mn>\n</math> meters above the ground at&nbsp;<math alttext=\"1.8\"><mn>1.8</mn></math> seconds; therefore,&nbsp;<math alttext=\"b equals 1.8\"><mi>b</mi><mo>=</mo><mn>1.8</mn></math> and <math alttext=\"c equals 51.84\"><mrow>\n\t<mi>c</mi>\n\t<mo>=</mo>\n\t<mn>51.84</mn>\n</mrow>\n</math>. Substituting&nbsp;<math alttext=\"1.8\"><mn>1.8</mn></math> for <math alttext=\"b\"><mi>b</mi>\n</math> and <math alttext=\"51.84\"><mn>51.84</mn>\n</math> for <math alttext=\"c\"><mi>c</mi>\n</math> in the equation <math alttext=\"h equals minus a left parenthesis t minus b right parenthesis squared plus c\"><mi>h</mi><mo>=</mo><mo>-</mo><mi>a</mi><msup><mfenced><mrow><mi>t</mi><mo>-</mo><mi>b</mi></mrow></mfenced><mn>2</mn></msup><mo>+</mo><mi>c</mi></math> yields <math alttext=\"h equals minus a left parenthesis t minus 1.8 right parenthesis squared plus 51.84\"><mi>h</mi><mo>=</mo><mo>-</mo><mi>a</mi><msup><mfenced><mrow><mi>t</mi><mo>-</mo><mn>1.8</mn></mrow></mfenced><mn>2</mn></msup><mo>+</mo><mn>51.84</mn></math>. It's also given that this softball hits the ground at&nbsp;<math alttext=\"3.6\"><mn>3.6</mn></math> seconds; therefore, <math alttext=\"h equals 0\"><mi>h</mi><mo>=</mo><mn>0</mn></math> when <math alttext=\"t equals 3.6\"><mi>t</mi><mo>=</mo><mn>3.6</mn></math>. Substituting <math alttext=\"0\"><mn>0</mn>\n</math> for <math alttext=\"h\"><mi>h</mi>\n</math> and&nbsp;<math alttext=\"3.6\"><mn>3.6</mn></math> for <math alttext=\"t\"><mi>t</mi>\n</math> in the equation <math alttext=\"h equals minus a left parenthesis t minus 1.8 right parenthesis squared plus 51.84\"><mi>h</mi><mo>=</mo><mo>-</mo><mi>a</mi><msup><mfenced><mrow><mi>t</mi><mo>-</mo><mn>1.8</mn></mrow></mfenced><mn>2</mn></msup><mo>+</mo><mn>51.84</mn></math> yields <math alttext=\"0 equals minus a left parenthesis 3.6 minus 1.8 right parenthesis squared plus 51.84\"><mn>0</mn><mo>=</mo><mo>-</mo><mi>a</mi><msup><mfenced><mrow><mn>3.6</mn><mo>-</mo><mn>1.8</mn></mrow></mfenced><mn>2</mn></msup><mo>+</mo><mn>51.84</mn></math>, which is equivalent to&nbsp;<math alttext=\"0 equals minus a left parenthesis 1.8 right parenthesis squared plus 51.84\"><mn>0</mn><mo>=</mo><mo>-</mo><mi>a</mi><msup><mfenced><mn>1.8</mn></mfenced><mn>2</mn></msup><mo>+</mo><mn>51.84</mn></math>, or <math alttext=\"0 equals minus 3.24 a plus 51.84\"><mn>0</mn><mo>=</mo><mo>-</mo><mn>3.24</mn><mi>a</mi><mo>+</mo><mn>51.84</mn></math>. Adding <math alttext=\"3.24 a\"><mrow>\n\t<mn>3.24</mn>\n\t<mi>a</mi>\n</mrow>\n</math> to both sides of this equation yields <math alttext=\"3.24 a equals 51.84\"><mn>3.24</mn><mi>a</mi><mo>=</mo><mn>51.84</mn></math>. Dividing both sides of this equation by <math alttext=\"3.24\"><mn>3.24</mn>\n</math> yields <math alttext=\"a equals 16\"><mi>a</mi><mo>=</mo><mn>16</mn></math>. Substituting <math alttext=\"16\"><mn>16</mn>\n</math> for <math alttext=\"a\"><mi>a</mi>\n</math> in the equation&nbsp;<math alttext=\"h equals minus a left parenthesis t minus 1.8 right parenthesis squared plus 51.84\"><mi>h</mi><mo>=</mo><mo>-</mo><mi>a</mi><msup><mfenced><mrow><mi>t</mi><mo>-</mo><mn>1.8</mn></mrow></mfenced><mn>2</mn></msup><mo>+</mo><mn>51.84</mn></math> yields <math alttext=\"h equals minus 16 left parenthesis t minus 1.8 right parenthesis squared plus 51.84\"><mi>h</mi><mo>=</mo><mo>-</mo><mn>16</mn><msup><mfenced><mrow><mi>t</mi><mo>-</mo><mn>1.8</mn></mrow></mfenced><mn>2</mn></msup><mo>+</mo><mn>51.84</mn></math>. Therefore,&nbsp;<math alttext=\"h equals minus 16 left parenthesis t minus 1.8 right parenthesis squared plus 51.84\"><mi>h</mi><mo>=</mo><mo>-</mo><mn>16</mn><msup><mfenced><mrow><mi>t</mi><mo>-</mo><mn>1.8</mn></mrow></mfenced><mn>2</mn></msup><mo>+</mo><mn>51.84</mn></math> represents the height above ground <math alttext=\"h\"><mi>h</mi>\n</math>, in meters, of this softball <math alttext=\"t\"><mi>t</mi>\n</math> seconds after it is launched.</p>\n<p style=\"text-align: left;\">Choice A is incorrect. This equation represents a situation where the maximum height is&nbsp;<math alttext=\"3.6\"><mn>3.6</mn></math> meters above the ground at <math alttext=\"0\"><mn>0</mn>\n</math> seconds, not <math alttext=\"51.84\"><mn>51.84</mn>\n</math> meters above the ground at&nbsp;<math alttext=\"1.8\"><mn>1.8</mn></math> seconds.</p>\n<p style=\"text-align: left;\">Choice B is incorrect. This equation represents a situation where the maximum height is <math alttext=\"51.84\"><mn>51.84</mn>\n</math> meters above the ground at <math alttext=\"0\"><mn>0</mn>\n</math> seconds, not&nbsp;<math alttext=\"1.8\"><mn>1.8</mn></math> seconds.</p>\n<p style=\"text-align: left;\">Choice C is incorrect and may result from conceptual or calculation errors.</p>","correct_answer":["D"],"has_media":false,"has_mathml":true,"has_table":false,"source_created_at":"2023-08-02T20:25:59.825000+00:00","source_updated_at":"2023-08-02T20:25:59.825000+00:00","options":[{"label":"A","content_html":"<p><math alttext=\"h equals minus t squared plus 3.6\"><mrow>\n\t<mi>h</mi>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mrow>\n\t\t\t<mo>-</mo>\n\t\t\t<msup>\n\t\t\t\t<mi>t</mi>\n\t\t\t\t<mn>2</mn>\n\t\t\t</msup>\n\t\t</mrow>\n\t\t<mo>+</mo>\n\t\t<mn>3.6</mn>\n\t</mrow>\n</mrow>\n</math></p>","ord":0},{"label":"B","content_html":"<p><math alttext=\"h equals minus t squared plus 51.84\"><mrow>\n\t<mi>h</mi>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mrow>\n\t\t\t<mo>-</mo>\n\t\t\t<msup>\n\t\t\t\t<mi>t</mi>\n\t\t\t\t<mn>2</mn>\n\t\t\t</msup>\n\t\t</mrow>\n\t\t<mo>+</mo>\n\t\t<mn>51.84</mn>\n\t</mrow>\n</mrow>\n</math></p>","ord":1},{"label":"C","content_html":"<p><math alttext=\"h equals minus 16 left parenthesis t minus 1.8 right parenthesis squared minus 3.6\"><mrow>\n\t<mi>h</mi>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mrow>\n\t\t\t<mo>-</mo>\n\t\t\t<mn>16</mn>\n\t\t\t<msup>\n\t\t\t\t<mfenced>\n\t\t\t\t\t<mrow>\n\t\t\t\t\t\t<mi>t</mi>\n\t\t\t\t\t\t<mo>-</mo>\n\t\t\t\t\t\t<mn>1.8</mn>\n\t\t\t\t\t</mrow>\n\t\t\t\t</mfenced>\n\t\t\t\t<mn>2</mn>\n\t\t\t</msup>\n\t\t</mrow>\n\t\t<mo>-</mo>\n\t\t<mn>3.6</mn>\n\t</mrow>\n</mrow>\n</math></p>","ord":2},{"label":"D","content_html":"<p><math alttext=\"h equals minus 16 left parenthesis t minus 1.8 right parenthesis squared plus 51.84\"><mrow>\n\t<mi>h</mi>\n\t<mo>=</mo>\n\t<mrow>\n\t\t<mrow>\n\t\t\t<mo>-</mo>\n\t\t\t<mn>16</mn>\n\t\t\t<msup>\n\t\t\t\t<mfenced>\n\t\t\t\t\t<mrow>\n\t\t\t\t\t\t<mi>t</mi>\n\t\t\t\t\t\t<mo>-</mo>\n\t\t\t\t\t\t<mn>1.8</mn>\n\t\t\t\t\t</mrow>\n\t\t\t\t</mfenced>\n\t\t\t\t<mn>2</mn>\n\t\t\t</msup>\n\t\t</mrow>\n\t\t<mo>+</mo>\n\t\t<mn>51.84</mn>\n\t</mrow>\n</mrow>\n</math></p>","ord":3}],"attribution":{"source_id":"cb_question_bank","source_name":"College Board digital SAT question bank (community dump)","rights_holder":"College Board","canonical_url":"https://satsuitequestionbank.collegeboard.org/","retrieved_from":"https://raw.githubusercontent.com/mdn522/sat-question-bank/main/data/cb-digital-questions.json","attribution":"SAT practice questions © College Board, from the official SAT Suite Question Bank. Retrieved via the community dump at github.com/mdn522/sat-question-bank.","disclaimer":"SAT® and PSAT/NMSQT® are trademarks registered by the College Board, which is not affiliated with, does not sponsor, and does not endorse this project.","license":"College Board copyright; source repository carries no licence. Local use only.","redistributable":false,"item_count":2017}}