{"id":"cb_practice_pdf:t4-math-m1-q14","source_id":"cb_practice_pdf","source_item_id":"t4-math-m1-q14","external_id":null,"ibn":null,"question_id":null,"program":"SAT","module":"math","domain_code":null,"domain":null,"skill_code":null,"skill":null,"difficulty":null,"score_band":null,"answer_type":"spr","answer_source":"rationale","layout_warning":null,"form_id":"cb_practice_pdf:test-4","module_number":1,"position":14,"stem":"24x+y = 48 6x+y = 7 2 The solution to the given system of equations is ( x, y). What is the value of y?","stimulus":"","stimulus_html":null,"stem_html":"<p>24x+y = 48 6x+y = 7 2 The solution to the given system of equations is ( x, y). What is the value of y?</p>","rationale_html":"<p>The correct answer is 80. Subtracting the second equation in the given system ( +) (- +) = - from the first equation yields 24 x y 6 x y 48 72, which is equivalent - + - =- =- to 24 x6 x y y 24, or 18x 24. Dividing each side of this equation =- - by 3 yiexlds 6 8. Substituting 8 for 6x in the second equation yields - + = = 8 y 72. Adding 8 to both sides of this equation yields y 80. Alternate approach: Multiplying each side of the second equation in the given + = system by 4 yields 24 4x 2y88. Subtracting the first equation in the given ( +) (- +) = - system from this equation yields 24 x4 y 24 x y 288 48, which is 37 SAT PRACTICE TEST #4 ANSWER EXPLANATIONS SAT ANSWER EXPLANATIONS nnn MATH: MODULE 1 - + - = = equivalent to 24 x24 x4 y y240, or 3y 240. Dividing each side of this = equation by 3 yields y 80.</p>","correct_answer":["80"],"has_media":false,"has_mathml":false,"has_table":false,"source_created_at":null,"source_updated_at":null,"options":[],"attribution":{"source_id":"cb_practice_pdf","source_name":"College Board full-length SAT practice tests (PDF)","rights_holder":"College Board","canonical_url":"https://satsuite.collegeboard.org/practice/practice-tests/paper","retrieved_from":"https://satsuite.collegeboard.org/practice/practice-tests/paper","attribution":"Full-length SAT practice tests 4–11 © College Board, published free at satsuite.collegeboard.org.","disclaimer":"Extracted from PDF layout: equations, figures and tables do not survive intact. Use the original PDFs for anything the text renders poorly. SAT® is a trademark registered by the College Board, which is not affiliated with and does not endorse this project.","license":"College Board copyright. Free to download; not licensed for redistribution.","redistributable":false,"item_count":905}}