{"id":"cb_practice_pdf:t11-math-m2-q15","source_id":"cb_practice_pdf","source_item_id":"t11-math-m2-q15","external_id":null,"ibn":null,"question_id":null,"program":"SAT","module":"math","domain_code":null,"domain":null,"skill_code":null,"skill":null,"difficulty":null,"score_band":null,"answer_type":"mcq","answer_source":"rationale","layout_warning":"Part of this question was typeset outside the text flow — a fraction, subscript or similar — and PDF extraction re-inserted it in the wrong place. The wording is reliable; the symbols may be out of order.","form_id":"cb_practice_pdf:test-11","module_number":2,"position":15,"stem":"15 y 350 300 250 200 150 100 50 x O 50 100 150 200 250 ‒50 ‒100 ‒150 ‒200 The graph shows the estimated boiling point y, in degrees Celsius, of a normal paraffin with a molecular weight of x grams per mole, where 1 # x # 280. Which statement is the best interpretation of the point 149.02,186.05? ^ h","stimulus":"","stimulus_html":null,"stem_html":"<p>15 y 350 300 250 200 150 100 50 x O 50 100 150 200 250 ‒50 ‒100 ‒150 ‒200 The graph shows the estimated boiling point y, in degrees Celsius, of a normal paraffin with a molecular weight of x grams per mole, where 1 # x # 280. Which statement is the best interpretation of the point 149.02,186.05? ^ h</p>","rationale_html":"<p>Choice B is correct. It’s given that the graph shows the estimated boiling point y, in degrees Celsius, of a normal paraffin with a molecular weight of x grams per 149.02,186.05 149.02 mole. It follows that for the point ^ h, represents the 186.05 molecular weight, in grams per mole, of a normal paraffin and represents its estimated boiling point, in degrees Celsius. Therefore, the best interpretation 149.02,186.05 of the point ^ h is that a normal paraffin with a molecular weight of 149.02 186.05 grams per mole has an estimated boiling point of degrees Celsius. Choice A is incorrect. This statement represents a situation where x, not y, represents the boiling point, in degrees Celsius, and y, not x, represents the molecular weight, in grams, per mole. Choice C is incorrect and may result from conceptual errors. Choice D is incorrect and may result from conceptual errors. 46 SAT PRACTICE TEST #11 ANSWER EXPLANATIONS SAT ANSWER EXPLANATIONS n MATH: MODULE 2</p>","correct_answer":["B"],"has_media":false,"has_mathml":false,"has_table":false,"source_created_at":null,"source_updated_at":null,"options":[{"label":"A","content_html":"<p>A normal paraffin with a molecular weight of 186.05 grams per mole has an estimated boiling point of 149.02 degrees Celsius.</p>","ord":0},{"label":"B","content_html":"<p>A normal paraffin with a molecular weight of 149.02 grams per mole has an estimated boiling point of 186.05 degrees Celsius.</p>","ord":1},{"label":"C","content_html":"<p>The minimum estimated boiling point for normal paraffins corresponds to a paraffin with a molecular weight of 149.02 grams per mole and an estimated boiling point of 186.05 degrees Celsius.</p>","ord":2},{"label":"D","content_html":"<p>The maximum estimated boiling point for normal paraffins corresponds to a paraffin with a molecular weight of 149.02 grams per mole and an estimated boiling point of 186.05 degrees Celsius.</p>","ord":3}],"attribution":{"source_id":"cb_practice_pdf","source_name":"College Board full-length SAT practice tests (PDF)","rights_holder":"College Board","canonical_url":"https://satsuite.collegeboard.org/practice/practice-tests/paper","retrieved_from":"https://satsuite.collegeboard.org/practice/practice-tests/paper","attribution":"Full-length SAT practice tests 4–11 © College Board, published free at satsuite.collegeboard.org.","disclaimer":"Extracted from PDF layout: equations, figures and tables do not survive intact. Use the original PDFs for anything the text renders poorly. SAT® is a trademark registered by the College Board, which is not affiliated with and does not endorse this project.","license":"College Board copyright. Free to download; not licensed for redistribution.","redistributable":false,"item_count":905}}