{"id":"cb_practice_pdf:t10-math-m1-q6","source_id":"cb_practice_pdf","source_item_id":"t10-math-m1-q6","external_id":null,"ibn":null,"question_id":null,"program":"SAT","module":"math","domain_code":null,"domain":null,"skill_code":null,"skill":null,"difficulty":null,"score_band":null,"answer_type":"spr","answer_source":"rationale","layout_warning":null,"form_id":"cb_practice_pdf:test-10","module_number":1,"position":6,"stem":"The function f is defined by f ( x) = x^2 +x+71. What is the value of f(2)?","stimulus":"","stimulus_html":null,"stem_html":"<p>The function f is defined by f ( x) = x^2 +x+71. What is the value of f(2)?</p>","rationale_html":"<p>The correct answer is 77. It’s given that the function f is defined by = 2+ +71 2 = 2 2+2+71 f^xh x x . Substituting 2 for x in function f yields f^ h ^ h , 2 =4+2+71 2 =77 which is equivalent to f^ h , or f^ h . Therefore, the value of f^2h is 77.</p>","correct_answer":["77"],"has_media":false,"has_mathml":false,"has_table":false,"source_created_at":null,"source_updated_at":null,"options":[],"attribution":{"source_id":"cb_practice_pdf","source_name":"College Board full-length SAT practice tests (PDF)","rights_holder":"College Board","canonical_url":"https://satsuite.collegeboard.org/practice/practice-tests/paper","retrieved_from":"https://satsuite.collegeboard.org/practice/practice-tests/paper","attribution":"Full-length SAT practice tests 4–11 © College Board, published free at satsuite.collegeboard.org.","disclaimer":"Extracted from PDF layout: equations, figures and tables do not survive intact. Use the original PDFs for anything the text renders poorly. SAT® is a trademark registered by the College Board, which is not affiliated with and does not endorse this project.","license":"College Board copyright. Free to download; not licensed for redistribution.","redistributable":false,"item_count":905}}